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Ulleksa [173]
2 years ago
13

Hi please help , With solution if it's ok

Mathematics
1 answer:
Snowcat [4.5K]2 years ago
5 0

<u>Answers </u><u>with </u><u>Method</u><u>:-</u>

1) Multiply the length value by 100,000.

2.5 \: hm = 2.5 \times 100000

=  >2.5 \: hm = 250000 \: mm

2) For this, divide the length value by 1000.

=  >  \frac{1800}{1000}

=  > 1.8 \: dam

3) For finding the approximate value, just multiply the value of length by 1.609.

=  >6450 \: m = (6450 \times 1.609) \: km

=  > 10380.27 \: km

4) Multiply the given mass value by 100.

=  > 1.2 \: kg = 1.2 \times 100

=  > 1200 \: g

5) Multiply the given value by 10,000.

4.37 \: dag = 4.37 \times 10000

=  > 43700 \: mg

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Based on the data given in the picture, calculate the area of the car track...
Verizon [17]

Refer to the diagram below. We need to find the areas of the green and blue regions, then subtract to get the area of the orange track only.

The larger green region is composed of a rectangle of dimensions 200 meters by 4+42+4 = 50 meters, along with two semicircles that combine to make a full circle. This circle has radius 25 meters.

The green rectangle has area 200*50 = 10000 square meters. The green semicircles combine to form an area of pi*r^2 = pi*25^2 = 625pi square meters. In total, the full green area is 10000+625pi square meters. I'm leaving things in terms of pi for now. The approximation will come later.

The blue area is the same story, but smaller dimensions. The blue rectangle has dimensions 200 meters by 42 meters, so its area is 200*42 = 8400 square meters. The blue semicircular pieces combine to a circle with area pi*r^2 = pi*21^2 = 441pi square meters. In total, the blue region has area 8400+441pi square meters.

After we figure out the green and blue areas, we subtract to get the orange region's area, which is the area of the track only.

orange area = (green) - (blue)

track area = (10000+625pi) - (8400+441pi)

track area = 10000+625pi - 8400-441pi

track area = (10000-8400) + (625pi - 441pi)

track area = 184pi + 1600 is the exact area in terms of pi

track area = 2178.05304826052 is the approximate area when you use the pi constant built into your calculator. If you use pi = 3.14 instead, then you'll get 2177.76 as the approximate answer. I think its better to use the more accurate version of pi. Of course, be sure to listen/follow your teachers instructions.

4 0
3 years ago
A right triangle has coordinates A(6, 0), B(0, 0), and C(0, 8). What is the perimeter of the triangle?
dimulka [17.4K]

Answer:

C

Step-by-step explanation:

From the given coordinates

A(6, 0), B(0, 0) then AB = 6 - 0 = 6

B(0, 0), C(0, 8) then BC = 8 - 0 = 8

To calculate AC use Pythagoras' theorem on the right triangle formed

AC² = AB² + BC² = 6² + 8² = 36 + 64 = 100

Take the square root of both sides, hence

AC = \sqrt{100} = 10

Perimeter = AB + BC + AC = 6 + 8 + 10 = 24 → C

5 0
3 years ago
a solid sphere is cut into 3 equal wedges. the volume of each wedge is V=4/9π^3. solve the formula for r
algol13

\\ \qquad\quad\sf{:}\dashrightarrow V=\dfrac{4}{9}πr^3

  • It is one third of the solid. sphere

\\ \qquad\quad\sf{:}\dashrightarrow V_{(Sphere)}

\\ \qquad\quad\sf{:}\dashrightarrow 3\left(\dfrac{4}{9}πr^3\right)

\\ \qquad\quad\sf{:}\dashrightarrow \dfrac{4}{3}\pi r^3

Now

\\ \qquad\quad\sf{:}\dashrightarrow \pi r^3=\dfrac{3V}{4}

\\ \qquad\quad\sf{:}\dashrightarrow r^3=\dfrac{3V}{4\pi}

\\ \qquad\quad\sf{:}\dashrightarrow r=\sqrt[3]{\dfrac{3V}{4\pi}}

4 0
3 years ago
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There are 12 donuts in a box 1/3 of them are chocolate, 1/4 of them are sprinkles, and the rest are glazed. How many donuts are
zmey [24]

Answer:

3 donuts are sprinkles

Step-by-step explanation:

1/3 of 12 is 4

1/4 of 12 is 3

4+3=7

12-7=5

Glazed=5

Chocolate=4

Sprinkles=3

5 0
2 years ago
Please help I’m stuck!!
jolli1 [7]

Answer:

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Step-by-step explanation:

a drug has a ratio of 115mg:5ml. This is equivalent to 23mg:1ml. 3g=3000mg, so we divide 3000 by 23 to get 130.434783. That is how many milliliters are needed. We round it to get 130 mL.

3 0
3 years ago
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