Given that the dealer sells a dozen tires for $240, every 3-tire set costs $60. There are six 2-tire sets in a dozen. Thus, his total revenue should be $360. The total profit is the difference between the total revenue and the total cost. The answer is therefore, the first choice, $120.
The value of <em>p </em>is 21
Step-by-step explanation:
ΔABC ~ ΔFGH
![\frac{ab}{fg} = \frac{bc}{gh} \\ \frac{35}{p} = \frac{10}{6} \\ p = \frac{35 \times 6}{10} \\ p = \frac{210}{10} \\ p = 21 \\ \\ or \\ \\ \frac{ab}{fg} = \frac{ac}{fh} \\ \frac{35}{p} = \frac{30}{18} \\ p = \frac{35 \times 18}{30} \\ p = \frac{630}{30} \\ p = 21](https://tex.z-dn.net/?f=%20%5Cfrac%7Bab%7D%7Bfg%7D%20%20%3D%20%20%5Cfrac%7Bbc%7D%7Bgh%7D%20%20%5C%5C%20%20%5Cfrac%7B35%7D%7Bp%7D%20%20%3D%20%20%5Cfrac%7B10%7D%7B6%7D%20%20%5C%5C%20p%20%3D%20%20%5Cfrac%7B35%20%5Ctimes%206%7D%7B10%7D%20%20%5C%5C%20p%20%3D%20%20%5Cfrac%7B210%7D%7B10%7D%20%20%5C%5C%20p%20%3D%2021%20%5C%5C%20%20%5C%5C%20or%20%5C%5C%20%20%5C%5C%20%20%5Cfrac%7Bab%7D%7Bfg%7D%20%20%3D%20%20%5Cfrac%7Bac%7D%7Bfh%7D%20%20%5C%5C%20%20%5Cfrac%7B35%7D%7Bp%7D%20%20%3D%20%20%5Cfrac%7B30%7D%7B18%7D%20%20%5C%5C%20p%20%3D%20%20%5Cfrac%7B35%20%5Ctimes%2018%7D%7B30%7D%20%20%5C%5C%20p%20%3D%20%20%5Cfrac%7B630%7D%7B30%7D%20%20%5C%5C%20p%20%3D%2021)
So, the value of <em>p</em> is 21
<em>Hope </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>
Answer:
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I don't know the answear sorry
Answer:
14
Step-by-step explanation:
answer is 14 trust me
Answer:
Sum of the first 15 terms = -405
Step-by-step explanation:
a + 3d = -15 (1)
a + 8d = -30 (2)
Where,
a = first term
d = common difference
n = number of terms
Subtract (1) from (1)
8d - 3d = -30 - (-15)
5d = -30 + 15
5d = -15
d = -15/5
= -3
d = -3
Substitute d = -3 into (1)
a + 3d = -15
a + 3(-3) = -15
a - 9 = -15
a = -15 + 9
a = -6
Sum of the first 15 terms
S = n/2[2a + (n − 1) × d]
= 15/2 {2×-6 + (15-1)-3}
= 7.5{-12 + (14)-3}
= 7.5{ -12 - 42}
= 7.5{-54}
= -405
Sum of the first 15 terms = -405