Problem One
Call the radius of the second can = r
Call the height of the second can = h
Then the radius of the first can = 1/3 r
The height of the first can = 3*h
A1 / A2 = (2*pi*(1/3r)*(3h)] / [2*pi * r * h]
Here's what will cancel. The twos on the right will cancel. The 3 and 1/3 will multiply to one. The 2 r's will cancel. The h's will cancel. Finally, the pis will cancel
Result A1 / A2 = 1/1
The labels will be shaped differently, but they will occupy the same area.
Problem Two
It seems like the writer of the problem put some lids on the new solid that were not implied by the question.
If I understand the problem correctly, looking at it from the top you are sweeping out a circle for the lid on top and bottom, plus the center core of the cylinder.
One lid would be pi r^2 = pi w^2 and so 2 of them would be 2 pi w^2
The region between the lids would be 2 pi r h for the surface area which is 2pi w h
Put the 2 regions together and you get
Area = 2 pi w^2 + 2 pi w h
Answer: Upper left corner <<<<< Answer
The answer is y= -4/7x+2
explanation
1. subtract 4x from both sides
2. divide every term by 7
Answer:
153 cm²
Step-by-step explanation:
The area is given by the formula ...
A = (1/2)bh
where b is the base length, and h is the height measured perpendicular to the base.
The diagram shows b = QR = 18 cm, and h = 17 cm. So, the area is ...
A = (1/2)(18 cm)(17 cm)
A = 153 cm²
Step-by-step explanation:
7z-5=4y-6
-4y=-6-7z+5
-4y=-1-7z
y=1/4+7/4z
y=7/4z+1/4
7z=4y-6+5
7z=4y-1
z=4/7y-1/7
The closest answer I can see you type is: 35/1.66666666
This is because you divide 21 by 18 which (if you divide 21 by 1.666666 you get 18) and whatever you do to 1 side, you do to the other, then you get 35/1.6666666
