Answer:
Step-by-step explanation:
note : P(C or D) = P(C)+P(D) - P(C and )
P(C or D) =0.29+0.47- 0
P(C or D) = 0.76
- two consecutive integers

<u>-4 and -3</u>
We use the formula a^2 - b^2 = ( a - b )( a + b );
We have a = 5m - 2 and b = 3m - 4;
<span>(5m-2)^2-(3m-4)^2 = (5m - 2 -3m + 4) x (5m-2 + 3m - 4) = (2m + 2)(8m - 6) = 2(m +1) x 2(4m - 3) = 4(m+1)(4m-3);
</span>
Answer:

Step-by-step explanation:


- In order to combine these two equations, an idea you need to keep in mind is finding a way of setting these equations as equal to each other. I saw that each equation shared a common value,
. In this case, we need to isolate
in the first equation so that both equations
.



- With this, we now know that both
and
are equal to
, so we can set them equal to each other.



- Reply to this if anything I'm saying or doing is confusing in any way, or if you find a mistake. :) Solve for
.







- Hopefully this answer is correct AND makes sense in terms of how I achieved it. Again, reply to this with any questions or mistakes I made and I'll do my best to answer or fix them.
Answer: d. 6
Explanation: you multiply each number by 6 every time