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Norma-Jean [14]
3 years ago
5

Evaluate. 33 + 11 - 10 ÷ 2 × 4 w = a0

Mathematics
1 answer:
Veronika [31]3 years ago
6 0

Answer:

24

Step-by-step explanation:

33 + 11 - 10 ÷ 2 × 4

Division is first.

33 + 11 - 5 × 4

Multiplication.

33 + 11 - 20

Add or subtract.

44 - 20

= 24

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Can someone please help me
Slav-nsk [51]

Answer:

B

Step-by-step explanation:

The  sum of the angles of the triangle add up to 180 degrees.

x and y are equal to each other in this type of the triangle.

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2 years ago
Sorry my brain is fried...
KiRa [710]

Answer:

1:D,2

2:B:She found that -3(9) is positive

3:D:Evaluated -2^2 as -4

4:Confused, is there supposed to be supplemental info?

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Suppose the sediment density (g/cm3 ) of a randomly selected specimen from a certain region is known to have a mean of 2.80 and
Irina18 [472]

Answer:

0.918 is the probability that the sample average sediment density is at most 3.00

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 2.80

Standard Deviation, σ = 0.85

Sample size,n = 35

We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling:

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.85}{\sqrt{35}} = 0.1437

P(sample average sediment density is at most 3.00)

P( x \leq 3.00) = P( z \leq \displaystyle\frac{3.00 - 2.80}{0.1437}) = P(z \leq 1.3917)

Calculation the value from standard normal z table, we have,  

P(x \leq 3.00) = 0.918

0.918 is the probability that the sample average sediment density is at most 3.00

4 0
3 years ago
A recipe for fruit punch calls for every 9 cups of grapefruit juice for every 4 cups of OJ. If 60 cups of OJ are used, then how
vampirchik [111]

Answer:

15 cups

Step-by-step explanation:

60/4=15

3 0
3 years ago
What is the extracts volume of the largest cone that can fit into a cube with edges of 10 inches
Aneli [31]
Volume of a cone = π r² h/3

I envisioned a cone inside a cube. I only identified the necessary value to compute for the exact volume of the largest cone.

Edges of the cube is 10 inches. When the circle part of the cone is placed in the circle, the diameter would be 10 inches also. I divided it by 2 to get the value of the radius, resulting to 5 inches.

The height of the cone is also the height of the cube. Thus, it is 10 inches.

Volume of the cone = 3.14 * (5in)² * 10in/3
V = 3.14 * 25in² * 3.33 in
V = 261.405 in³ or 261.41 in³  VOLUME OF THE LARGEST CONE THAT CAN FIT IN A 10 INCH CUBE

4 0
3 years ago
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