Answer:
The acceleration is 
Explanation:
From the question we are told that
The length of the stick is 
The mass of the stick is 
The angular displacement is 
Generally the torque of this uniform stick after this displacement is mathematically represented as
![\tau = \frac{1}{2} * d * [m*g]* sin (90 - \theta)](https://tex.z-dn.net/?f=%5Ctau%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2A%20%20d%20%20%2A%20%20%5Bm%2Ag%5D%2A%20%20sin%20%2890%20-%20%5Ctheta%29)
![\tau = \frac{1}{2} * 1.9 * [3.1*9.8]* sin (90 - 23.4)](https://tex.z-dn.net/?f=%5Ctau%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2A%20%201.9%20%20%2A%20%20%5B3.1%2A9.8%5D%2A%20%20sin%20%2890%20-%2023.4%29)

Generally the moment of inertia of the uniform stick is mathematically represented as

=> 
=> 
Generally the angular acceleration is mathematically represented as

=> 
=> 
Answer:
Spring potential energy = 7.875Nm
Explanation:
<u>Given the following data;</u>
Extension, e = 15cm to meters = 15/100 = 0.15m
Spring constant, k = 350n/m
To find the force;
Force = spring constant * extension
Force = 350 * 0.15
Force = 52.5 Newton.
Now to find the spring potential energy we would use the formula below;
Spring potential energy = force * extension
Substituting into the equation, we have;
Spring potential energy = 52.5 * 0.15
<em>Spring potential energy = 7.875Nm</em>
Answer:

Explanation:
First, let's find the voltage through the resistor using ohm's law:

AC power as function of time can be calculated as:
(1)
Where:

Because of the problem doesn't give us additional information, let's assume:

Evaluating the equation (1) in t=3600 (Because 1h equal to 3600s):

The energy of a light wave is calculated using the formula
E = hc/λ
h is the Planck's constant
c is the speed of light
λ is the wavelength
For the ir-c, the range is
<span>6.63 x 10^-34 (3x10^8) / 3000 = 6.63 x 10 ^-29 J
</span>6.63 x 10^-34 (3x10^8) / 1000000 = 1.99 x 10^-31 J
For the ir-a, the range is
6.63 x 10^-34 (3x10^8) / 700 = 2.84 x 10^-28 J
6.63 x 10^-34 (3x10^8) / 1400 = 1.42 x 10^-28 J