The increase in gravitational potential energy for an object of mass m is given by
where
is the increase in altitude of the object.
In our problem, m=3.0 kg,
and
(approximated value), so we have
Before taking a pressure reading, it is necessary for the technician to first allow the temperature of the cylinder to stabilize to room temperature because a comparison with a temperature-pressure chart is only valid and true when both temperature and pressure of the refrigerant are stable.
<span>After an exoplanet has been identified using a given detection method, scientists attempt to identify the basic properties of the planet which can tell us what it might be made of, how hot it might be, whether or not it contains an atmosphere, how that atmosphere might behave, and finally, whether the planet may be suitable for life. It is often useful to first determine basic properties of the parent star (such as mass and distance from the Earth). This is then followed by the use of planetary detection methods to calculate planetary mass, radius, orbital radius, orbital period, and density. The density calculation will provide clues as to what the planet is made of and whether or not it contains a significant atmosphere.
Mass and Distance of Parent Star
The mass and distance of an exoplanet's parent star must often be calculated first, before certain measurements of the exoplanet can be made. For example, determining the star's distance is an important step in determining a star's mass (see below). Knowing the mass of a star then allows the mass of the planet to be measured, for example when using the Radial Velocity Method.</span>
Answer:
increases by a factor of 
Explanation:
First we need to find the initial velocity for it to stop at the distance 2d using the following equation of motion:
where v = 0 m/s is the final velocity of the package when it stops, 
is the initial velocity of the package when it, a is the deceleration, and 
is the distance traveled.
So the equation above can be simplified and plug in Δs = d, 
for the 1st case
(1)
For the 2nd scenario where the ramp is changed and distance becomes 2d, 
(2)
let equation (2) divided by (1) we have:
So the initial speed increases by . If the deceleration a stays the same and time is the ratio of speed over acceleration a
The time would increase by a factor of
1.085m
Explanation:
Using
a= lambda/sinစ
Sinစ= (587.5*10^-9) x 0.75*10^-3
= 0.000783
Sinစ=0.875*10^-3/d
0.000783= 0.875/d
d= 1.085m
