3 years ago

What type of mage can never be formed by a converging lens?

Physics

1 answer:

Irina18 [472]3 years ago

4 0

Answer: Real image

Explanation:

converging lens will only produce a real image if the object is located beyond the focal point (i.e., more than one focal length away).

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Answer:

706.68 N

Explanation:

By Hooke's law,

$F = ke$

$k=\dfrac{F}{e}$

Using the values in the question,

$k=\dfrac{265\text{ N}}{0.15 \text{ m}}=1766.7\text{ N/m}$

When e = 0.4 m,

$F = 1766.7\text{ N/m}\times0.4\text{ m}=706.68\text{ N}$

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3 years ago

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The answer is

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A long thin rod of mass M and length L is situated along the y axis with one end at the origin. A small spherical mass m1 is pla

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Answer:

$= - 5.65\times 10^{-2} J$

Explanation:

Given data:

L =2.00 *10^4 m

d = 18*10^4 m

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$U =- G \frac{m_1 m_2}{r}$

mass per unit length is given as

$\sigma = \frac{M}{L} = \frac{18 \times 10^6}{2\times 10^4 m} = 900 kg/m$

calculating potential energy

$dU ==-G\int_{16\times 10^4}^{18\times 10^4} \frac{m_1 *dm}{r}$

$=-G\int_{16\times 10^4}^{18\times 10^4} \frac{m_1 *\sigma dr}{r}$

$=-G*m_1*\sigma\int_{16\times 10^4}^{18\times 10^4} \frac{dr}{r}$

$=-G*m_1*\sigma \left | ln r \right |_{16\times 10^4}^{18\times 10^4}$

$=-G*m_1*\sigma ln(1.125)$

$=-6.673 \times 10^{-11}*8*10^6*900*ln(1.125)$

$= - 5.65\times 10^{-2} J$

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3 years ago

Cuando habla una persona, ¿por qué identificas que se trata de un hombre,una mujer o un niño

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Answer:

Lo ases por su voz

Explanation:

Creo ,,,,,,

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2 years ago