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dusya [7]
3 years ago
11

Which types of heat transfer involve heat flow from hot objects to colder objects? A. convection, conduction, and radiation B. c

onvection and radiation, but not conduction C. convection, but not conduction or radiation D. convection and conduction, but not radiation
Physics
2 answers:
bulgar [2K]3 years ago
6 0

its all 3 convection, radiation, and conduction  

Soloha48 [4]3 years ago
4 0
B is definitely the answer. Please let it be
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A tennis ball is released from a height of 4.0 m above the floor. After its third bounce off the floor, it reaches a height of 1
diamong [38]

Answer:

The percentage of its mechanical energy does the ball lose with each bounce is 23 %

Explanation:

Given data,

The tennis ball is released from the height, h = 4 m

After the third bounce it reaches height, h' = 183 cm

                                                                       = 1.83 m

The total mechanical energy of the ball is equal to its maximum P.E

                                      E = mgh

                                          = 4 mg

At height h', the P.E becomes

                                      E' = mgh'

                                           = 1.83 mg

The percentage of change in energy the ball retains to its original energy,

                                 \Delta E\%=\frac{1.83mg}{4mg}\times100\%

                                  ΔE % = 45 %

The ball retains only the 45% of its original energy after 3 bounces.

Therefore, the energy retains in each bounce is

                                   ∛ (0.45) = 0.77

The ball retains only the 77% of its original energy.

The energy lost to the floor is,

                                E = 100 - 77

                                   = 23 %

Hence, the percentage of its mechanical energy does the ball lose with each bounce is 23 %      

5 0
4 years ago
Trên bóng đèn có ghi là 12v -6w. Khi đèn sáng bình thường thì dòng điện chạy qua đèn có cường độ là
mrs_skeptik [129]

Answer:

I=P/U=6/12=0.5(A)

Explanation: P=UI ( CÔNG SUẤT = HIỆU ĐIỆN THẾ NHÂN VỚI C Đ D Đ)

4 0
3 years ago
In a series RLC ac circuit, a second resistor is connected in series with the resistor previously in the circuit. As a result of
AnnyKZ [126]

Answer:

* The first thing we observe is that the frequency response does not change

* The current that circulates in the circuit decreases due to the new resistance at the resonance point,

          Z = R + R₂

Explanation:

The impedance of a series circuit is

          Z₀² = R² + (X_L-X_C) ²

when we place another resistor in series the initial resistance impedance changes to

          Z² = (R + R₂) ² + (X_L - X_C) ²

           

let's analyze this expression

* The first thing we observe is that the frequency response does not change

* The current that circulates in the circuit decreases due to the new resistance at the resonance point,

          Z = R + R₂

8 0
3 years ago
Ac circuits have… A. Two current paths. B many current paths. C one current path. D two voltage paths
kow [346]
I would say…

B) they have many current paths
3 0
3 years ago
Three small objects are arranged along a uniform rod of mass m and length L. one of mass m at the left end, one of mass m at the
yKpoI14uk [10]

Answer:

See answer below

Explanation:

Hi there,

To get started, recall the Center of Mass formula for two masses:

x_c_m = \frac{m_1x_1+m_2x_2}{m_1+m_2}  where m is mass and x is displacement <em>from the center of the shape.</em>

Since masses at the center of a geometric shape have a displacement (x) value of 0, as the mass is already of the center, and does not affect Xcm. So, we can disregard the central mass, hence we use the above formula for two masses.

We can arbitrarily define left to be a negative (-) displacement, and vice versa for right direction. We proceed with the formula:x_c_m=\frac{(-L/2)m+(L/2)2m}{m+2m} =\frac{(L/2)(-m+2m)}{3m} \\ x_c_m=\frac{L(m)}{6m} =\frac{L}{6}

Since we defined left (-) and right (+), we notice the center of mass is (+) value. This makes sense, as there is slightly more mass on the right side. Hence, you should place a support 1/6 of the rod's length away from the rod's center.

Study well and persevere.

thanks,

4 0
4 years ago
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