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Zina [86]
3 years ago
9

Translate the following into algebraic expressions: The first class has a kids in it, the second has b kids in it, and the third

class has c kids in it. The kids from all three classes are divided equally between two buses. How many kids are in each bus?
Mathematics
1 answer:
Studentka2010 [4]3 years ago
4 0

Answer:

(a + b + c)/2

Step-by-step explanation:

Number of kids in first class: a

Number of kids in second class: b

Number of kids in third class: c

The total number of kids in all classes is: a + b + c

The total number of kids is divided equally between 2 buses:

(a + b + c)/2

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Step-by-step explanation:

We know that scale factor = (image)/(preimage).

Substituting in what we have,

5=\frac{R'S'}{RS}\\\\5=\frac{40}{RS}\\\\RS=\boxed{8}

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Find the missing length of the triangle. (I need a step by step explanation)
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If a couple were planning to have three​ children, the sample space summarizing the gender outcomes would​ be: bbb,​ bbg, bgb,​
marusya05 [52]

Answer:

(a) The sample space is: S = {bb, bg, gb, gg}

(b) The probability that the couple has two girl children is 0.25.

(c) The probability that the couple has exactly 1 boy and 1 girl child is 0.50.

Step-by-step explanation:

A boy child is denoted by, <em>b</em>.

A girl child is denoted by, <em>g</em>.

(a)

A couple has two children.

The sample space for the possible gender of the two children are:

The couple can have two boys, two girls or 1 boy and 1 girl.

So the sample space is:

S = {bb, bg, gb, gg}

(b)

It is provided that the outcomes of the sample space <em>S</em> are equally likely, i.e. each outcome has the same probability of success.

Compute the probability that the couple has two girl children as follows:

P (2 Girls) = Favorable no. of outcomes ÷ Total no. of outcomes

                =\frac{1}{4} \\=0.25

Thus, the probability that the couple has two girl children is 0.25.

(c)

Compute the probability that the couple has exactly 1 boy and 1 girl child as follows:

P (1 boy & 1 girl) = Favorable no. of outcomes ÷ Total no. of outcomes

                          =\frac{2}{4} \\=0.50

Thus, the probability that the couple has exactly 1 boy and 1 girl child is 0.50.

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1 - (1/4 + 2/3)

1 - (3/12 + 8/12)

1 - 11/12

1/12 left

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Factorise the following expressions​.
Setler79 [48]

Answer:

Q.1 a²+10a+24

splitting the middle.

a²+6a+4a+24

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splitting the middle

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