Answer:
The minimum sample size needed is
. If n is a decimal number, it is rounded up to the next integer.
is the standard deviation of the population.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Z-table as such z has a p-value of
.
That is z with a pvalue of
, so Z = 1.645.
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
How large a sample must she select if she desires to be 90% confident that her estimate is within 4 ounces of the true mean?
A sample of n is needed, and n is found when M = 4. So






The minimum sample size needed is
. If n is a decimal number, it is rounded up to the next integer.
is the standard deviation of the population.
The answer is C . -7r^2 + 12r -8
<span>The best answer is C.add 2 to both sides of the equation.
</span>5=x-2
5+2=x-2+2
7=x-0
x=7
Answer:
Explanation:
First we find what x is:
x + 1/x = 12
x + 1 = 12x
1 = 12x - x
1 = 11x
1/11 = x
Or x = 1/11
Plug x value in x^3 + 1/x^3
(1/11)^3 + 1/(1/11)^3
= (1^3/11^3)+ 1/(1^3/11^3)
= (1/1331 + 1)/1/1331
= (1/1331 + 1331/1331)/1/1331
= 1332/1331 x 1331/1
= 1332/1
= 1332
Therefore, x^3 + 1/x^3 = 1332