Answer:
It takes 8.204 minutes for light to travel from the Sun to Earth
Explanation:
The speed of light is 300000 km/s and the nearest star to the Earth is the Sun which is 149.67 million km. therefore it takes about
147.67×10⁶/300000 = 492.233 seconds for light from the Sun to reach Earth or 8.204 minutes
The other next nearest star is Alpha Centauri which is 4 light years away
Answer:
Luminol
Explanation:
is a chemical that exhibits chemiluminescence, with a blue glow, when mixed with an appropriate oxidizing agent.
Answer:
The answer is C "think about the problem first, systematically consider all factors, and form a hypothesis"
Explanation:
In physics there is some basic fomula that sir Isacc Newton proposed under the topic of motion. The three formulas are below;
<em>1) v=u+at</em>
<em>2)v^2=u^2+2as</em>
<em>3)s=ut+(1/2)(at^2)</em>
the variables are explained below;
u= initial velocity of the body
a=acceleration/Speed of the body
t= time taken by the body while travelling
s= displacement of the body.
Therefore to solve keatons problem, the factors(variables) in the formulas above need to be systematically considered. Since the ball was dropped from the top of the building, the initial velocity is 0 because the body was at rest. Also the acceleration will be acceleration due to gravity (9.8m/s^2)
So, the final velocity of the ball when it is 10.0 m above the ground approximately <u>26.2 m/s</u>.
<h3>Introduction</h3>
Hi ! In this question, I will help you. This question uses the principle of final velocity in free fall. Free fall occurs only when an object is dropped (without initial velocity), so the falling object is only affected by the presence of gravity. In general, the final velocity in free fall can be expressed by this equation :
With the following condition :
- v = final velocity (m/s)
- h = height or any other displacement at vertical line (m)
- g = acceleration of the gravity (m/s²)
<h3>Problem Solving</h3>
We know that :
= initial height = 45.0 m
= final height = 10.0 m- g = acceleration of the gravity = 9.8 m/s²
Note :
At this point 10 m above the ground, the object can still complete its movement up to exactly 0 m above the ground.
What was asked :
- v = final velocity = ... m/s
Step by Step
<h3>Conclusion</h3>
So, the final velocity of the ball when it is 10.0 m above the ground approximately 26.2 m/s.
<h3>See More :</h3>
Newton taught us that Force = (mass) x (acceleration)
Force = (0.2) x (20) = <em>4 newtons</em> .
Something to think about: The ball can only accelerate while the club-face
is in contact with it. Once the ball leaves the club, it can't accelerate any more,
because the force against it is gone.
