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kompoz [17]
3 years ago
9

Understand that the acceleration vector is in the direction of the change of the velocity vector. In one dimensional (straight l

ine) motion, acceleration is accompanied by a change in speed, and the acceleration is always parallel (or antiparallel) to the velocity. When motion can occur in two dimensions (e.g. is confined to a tabletop but can lie anywhere in the x-y plane), the definition of acceleration is
Physics
1 answer:
MaRussiya [10]3 years ago
8 0

Answer:

 a = √ (a_t² + a_c²)

a_t = dv / dt ,    a_c = v² / r  

Explanation:

In a two-dimensional movement, the acceleration can have two components, one in each axis of the movement, so the acceleration can be written as the components of the acceleration in each axis.

            a = aₓ i ^ + a_y j ^

Another very common way of expressing acceleration is by creating a reference system with a parallel axis and a perpendicular axis. The axis called parallel is in the radial direction and the perpendicular axis is perpendicular to the movement, therefore the acceleration remains

         a = √ (a_t² + a_c²)

where the tangential acceleration is

           a_t = dv / dt

the centripetal acceleration is

          a_c = v² / r

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A brick sits on the top of a hill with a gravitational potential energy of 245 J. To determine the gravitational potential of th
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Answer:

The mass of the object, its acceleration due to gravity and the distance between the top of the hill and the ground level.

Explanation:

gravitational potential energy is the energy possessed by a body under influence of gravitational force by virtue of its position.

In order to determine the gravitational potential energy of the brick, we must know the mass (m) of the brick, its acceleration due to gravity (g) since it is acting under the influence of gravitational force and the distance between the top of the hill and the ground level. (The height).

Potential energy of a body is calculated as mass × acceleration due to gravity × height.

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Which shows zero as significant digits? Check all that apply.
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Answer:

Explanation:

0.02

0.604

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The component that allows a car to execute complex maneuvers is __________ .
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Alden, a passenger on a yacht moored 15 miles due north of a straight, east-west
Ghella [55]

Answer:

To minimize the travel time from the yacht to the hospital, the motorboat should head in a direction of 12.83 degrees west of south.

Explanation:

If we assume that both the motorboat and ambulance will be moving at a constant speed, we can calculate the time that each one will take to travel a given distance using the following equation:

time=\frac{distance}{speed}

Then the total travel time from the yacht to the hospital will be the motorboat travel time plus the ambulance travel time

t=t_m+t_a

t=\frac{d_m}{s_m} +\frac{d_a}{s_a}

First we must write the total travel time in terms of the motorboat's direction (Θ).

cos(\theta)=\frac{15}{d_m}

d_m=\frac{15}{cos(\theta)}=15 sec(\theta)

d_a=60-d_1

tan(\theta)=\frac{d_1}{15}

d_1=15tan(\theta)

d_a=60-15tan(\theta)

t=t_m+t_a

t=\frac{d_m}{s_m} +\frac{d_a}{s_a}

t=\frac{15sec(\theta)}{20} + \frac{60-15tan(\theta)}{90}

t=\frac{15}{20}sec(\theta) + \frac{60}{90}-\frac{15}{90}tan(\theta)

t=\frac{3}{4}sec(\theta)-\frac{1}{6}tan(\theta) + \frac{2}{3}

 

So this last equation represents the variation of the total travel time as a function of the motorboat's direction.

To find the equation's minimum point (which would be the direction with the minimum total travel time), we must find \frac{dt}{d\theta} and then find its roots (its x-interceptions).

\frac{dt}{d\theta}=\frac{d}{d\theta} (\frac{3}{4}sec(\theta)-\frac{1}{6}tan(\theta) + \frac{2}{3})

\frac{dt}{d\theta}=\frac{3}{4}sec(\theta)tan(\theta)-\frac{1}{6}sec^2(\theta)

\frac{dt}{d\theta}=sec(\theta)(\frac{3}{4}tan(\theta)-\frac{1}{6}sec(\theta))

Now let's find the values of x which make \frac{dt}{d\theta}=0

\frac{dt}{d\theta}=sec(\theta)(\frac{3}{4}tan(\theta)-\frac{1}{6}sec(\theta))=0

As sec(\theta) is never equal to zero, then \frac{dt}{d\theta} would be zero when

\frac{3}{4}tan(\theta)=\frac{1}{6}sec(\theta)

Graphing both equations we can find their interceptions and this would the value we're looking for.

In the attached images we can see that \theta=0.224 rad=12.83° is the minimum point for t(\theta). Then, to minimize the travel time from the yacht to the hospital, the motorboat should head in a direction of 12.83 degrees west of south.

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3 years ago
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