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Sergio [31]
3 years ago
12

Which best describes accuracy?

Physics
2 answers:
Ierofanga [76]3 years ago
7 0
The dependence of a measured value on a controlled value should be the correct answer. 
azamat3 years ago
4 0

Just took the test and its D

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2 Points
Tom [10]
The answers are A and E!
6 0
2 years ago
A ball rolls over the edge of a platform with only a horizontal velocity. The height of the platform is 1.60m and the horizontal
AysviL [449]

Answer:

v = 46.99 m/s

Explanation:

The velocity of the ball just before it touches the ground, is given by the following formula:

v=\sqrt{v_x^2+v_y^2}           (1)

vx: horizontal component of the velocity

vy: vertical component of the velocity

The vertical component vy is calculated by using the following formula:

v_y^2=v_{oy}^2+2gh   (2)

vy: final velocity

voy: initial vertilal velocity = 0m/s  (because it is a semi parabolic motion)

g: gravitational acceleration = 9.8 m/s^2

h: height = 1.60m

You replace the values of the parameters in the equation (2):

v_y=2(9.8m/s^2)(1.60m)=31.36\frac{m}{s}

vx is calculated by using the information about the horizontal range of the ball:

R=v_o\sqrt{\frac{2h}{g}}    (3)

R: horizontal range of the ball = 20.0 m

You solve the previous equation for vo, the initial horizontal velocity:

v_o=R\sqrt{\frac{g}{2h}}=(20.0m)\sqrt{\frac{9.8m/s^2}{2(1.60m)}}\\\\v_o=35\frac{m}{s}

The horizontal component of the velocity is constant in the complete trajectory, hence, you have that

vx = vo = 35 m/s

Finally, you replace the values of vx and vy in the equation (1):

v=\sqrt{(35m/s)^2+(31.36m/s)^2}=46.99\frac{m}{s}

The velocity of the ball just before it touches the ground is 46.99 m/s

5 0
3 years ago
A large pot is placed on a stove and 1.2 kg of water at 14°C is added to the pot. The temperature of the water is raised evenly
CaHeK987 [17]

Answer:

100°heat

Explanation:

since when i calculate this and that, the answer is 100° heat.

sorry if it is inconvenient

3 0
3 years ago
The average force of a baseball is 18.9 N . It’s mass is 0.145kg fine the acceleration in m/s^2
Artyom0805 [142]

Answer:

the acceleration is 130.3m/s²

Explanation:

Given data

Force F= 18.9N

Mass of ball m= 0.145kg

Acceleration a=?

Applying the Newton's second law of motion

"The rate of change of momentum of a body is proportional to the external force".

F=ma

a= F/m

a= 18.9/0.142

a= 130.3m/s²

3 0
3 years ago
BABY BABY BABY OOOHHHH I THOUGHT THAT U WOULD ALWAYS BE MINE
kenny6666 [7]

Answer:

Don't you worry, 'cause everything's gonna be alright, ai-a'ight

Be alright, ai-a'ight

Explanation:

6 0
2 years ago
Read 2 more answers
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