consider the motion in x-direction
= initial velocity in x-direction = ?
X = horizontal distance traveled = 100 m
= acceleration along x-direction = 0 m/s²
t = time of travel = 4.60 sec
Using the equation
X = t + (0.5) t²
100 = (4.60)
= 21.7 m/s
consider the motion along y-direction
= initial velocity in y-direction = ?
Y = vertical displacement = 0 m
= acceleration along x-direction = - 9.8 m/s²
t = time of travel = 4.60 sec
Using the equation
Y = t + (0.5) t²
0 = (4.60) + (0.5) (- 9.8) (4.60)²
= 22.54 m/s
initial velocity is given as
= sqrt(()² + ()²)
= sqrt((21.7)² + (22.54)²) = 31.3 m/s
direction: θ = tan⁻¹(22.54/21.7) = 46.12 deg
Answer:
A. It must be zero
Explanation:
A spacecraft leaves the solar system at a velocity of 1,500 m/s. The net force on this spacecraft is zero. What can we say about the spacecraft's acceleration?
According to Newton's second law
Force = Mass × acceleration
If the net force is zero
0 = mass × acceleration
0 = ma
a = 0/m
a = 0m/s²
this shows that the acceleration will be zero If the net force is zero
Answer:
wavelength 
= 437.27 nm
Explanation:
given data
first bright fringe = 2.96 mm
slit separation = 0.325 mm
distance D = 2.20 m
solution
we know that this is double slit experiment
so we apply here Fringe width formula that is
β = 
....................1
is Wavelength of light and D is Distance between screen and slit and d is slit width
so put here value and we get
= 
= 437.27 × 
m
wavelength = 437.27 nm
Explanation:
The answer is in the pic above
Answer:
d / λ = 26.7
Explanation:
In Young's double slit experiment, constructive interference is described by the expression
d sin θ = m λ
In the case of destructive interference we must add half wavelength (λ/2)
d siyn θ = (m + ½) λ
Let's clear
d / λ = (m + ½) / sin θ
Let's calculate
d / λ = (2+ ½) / sin 5.4
d / λ = 5 / (2 sin 5.4)
d / λ = 26.7
