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beks73 [17]
3 years ago
7

If an object moving at 12 m/s has a kinetic energy of 72 j what is the mass

Physics
1 answer:
EleoNora [17]3 years ago
5 0
Simply, apply the formula E = \frac{1}{2}mv^{2} and insert the values of m = mass, v = velocity and E = Energy.
The result will be 72J =  \frac{1}{2}m(12m/s)^{2}, m = 1 kg
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3 years ago
In an elastic collision, a 400-kg bumper car collides directly from behind with a second, identical bumper car that is traveling
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Answer:

v₁ = 3.5 m/s

v₂ = 6.4 m/s

Explanation:

We have the following data:

m₁ = mass of trailing car = 400 kg

m₂ = mass of leading car = 400 kg

u₁ = initial speed of trailing car = 6.4 m/s

u₂ = initial speed of leading car = 3.5 m/s

v₁ = final speed of trailing car = ?

v₂ = final speed of leading car = ?

The final speed of the leading car is given by the following formula:

v_2=\frac{2m_1}{m_1+m_2}u_1-\frac{m_1-m_2}{m_1+m_2}u_2\\\\v_2=\frac{(2)(400\ kg)}{400\ kg+400\ kg}(6.4\ m/s)-\frac{400\ kg-400\ kg}{400\ kg + 400\ kg}(3.5\ m/s)

<u>v₂ = 6.4 m/s</u>

The final speed of the leading car is given by the following formula:

v_1=\frac{m_1-m_2}{m_1+m_2}u_1+\frac{2m_2}{m_1+m_2}u_2\\\\v_1=\frac{400\ kg-400\ kg}{400\ kg + 400\ kg}(6.4\ m/s)+\frac{(2)(400\ kg)}{400\ kg+400\ kg}(3.5\ m/s)

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As, we know that the same charges repeal each other both of the balloons with be apart from each other.

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Answer:

d

Explanation:

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