1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
liraira [26]
3 years ago
13

Hey guys I really really need help with this question for ASAP! Explain what chart junk is and how it differs from the kind of i

tems you should include in your graphs. Provide four examples?
the second question is Explain what chart junk is and how it differs from the kind of items you should include in your graphs. Provide four examples.
Physics
2 answers:
Step2247 [10]3 years ago
4 0

Answer:

Chartjunk refers to all visual elements in charts and graphs that are not necessary to comprehend the information represented on the graph, or that distract the viewer from this information.

Explanation:

Ahat [919]3 years ago
3 0
I found a definition: Chartjunk<span> refers to all visual elements in </span>charts<span> and graphs that are not necessary to comprehend the information represented on the graph, or that distract the viewer from this information.</span>
You might be interested in
Which of the following describes a role of gravity in the formation of our solar system?
Black_prince [1.1K]
I think the answer is A because it is gravity that caused the planets to form and start orbiting around the nearest star which is the sun
5 0
4 years ago
Read 2 more answers
Filtration is used to separate mixtures based on _____.
sergejj [24]
Based on particle size.
its where a solid is separated from a liquid. filter paper has tiny holes only allowing small molecules to pass
8 0
3 years ago
Read 2 more answers
A 1800-kg Jeep travels along a straight 500-m portion of highway (from A to B) at a constant speed of 10 m/s. At B, the Jeep enc
vladimir1956 [14]

Answer:

3600N

Explanation:

F=m\frac{v^2}{r}

4 0
3 years ago
A heat engine with 0.300 mol of a monatomic ideal gas initially fills a 1000 cm3 cylinder at 500 K . The gas goes through the fo
LuckyWell [14K]

Complete Question:

A heat engine with 0.300 mol of a monatomic ideal gas initially fills a 1000 cm3 cylinder at 500 K . The gas goes through the following closed cycle: - Isothermal expansion to 5000 cm3. - Isochoric cooling to 400 K . - Isothermal compression to 1000 cm3. - Isochoric heating to 500 K .

a) what is the work for one cycle

b) what is the thermal efficiency

Answer:

a) Work done for 1 cycle = 402.13

b) Thermal efficiency = 20%

Explanation:

Number of moles, n = 0.300 mol

Initial Volume, V₁ = 1000 cm³

Temperature, T = 500 K

Isothermal expansion to 5000 cm³

Final volume, V₂ = 5000 cm³

R = 8.314 J/ mol.K

Work done, W = nRT ln(V₂/V₁)

W = (0.3 * 8.314 * 500) * ln(5000/1000)

W = 1247.1 * ln5

W₁ = 2007.13 J

Isochoric cooling

In an Isochoric process, volume is constant i.e. V₂ = V₁ = V

W = nRT ln(V/V)

But  ln(V/V) = ln 1 = 0

Work done, W₂ = 0 Joules

Isothermal Compression to 1000 cm³

V₂ = 1000 cm³

V₁ = 5000 cm³

W = nRT ln(V₂/V₁)

W = 0.3 * 8.314 * 400 ln(1000/5000)

W₃ = -1605 J

Isochoric heating to 500 K

Since there is no change in volume, no work is done

W₄ = 0 J

a) Work done for 1 cycle

W = W₁ + W₂ + W₃ + W₄

W = 2007.13 + 0 + 0 -1605+0

W = 402.13 Joules

b) Thermal efficiency

Thermal efficiency = (Net workdone for 1 cycle)/(Heat absorbed)

Heat absorbed = Work done due to thermal expansion = 2007.13 J

Thermal efficiency = 402.13/2007.13

Thermal efficiency = 0.2

Thermal efficiency = 0.2 * 100% = 20 %

3 0
4 years ago
Determine the binding energy per nucleon of an mg-24 nucleus. the mg-24 nucleus has a mass of 24.30506. a proton has a mass of 1
My name is Ann [436]

The mass of Mg-24 is 24.30506 amu, it contains 12 protons and 12 neutrons.

Theoretical mass of Mg-24:

The theoretical mass of Mg-24 is:

Hydrogen atom mass = 12 × 1.00728 amu = 12.0874 amu

Neutron mass = 12 x 1.008665 amu = 12.104 amu

Theoretical mass = Hydrogen atom mass + Neutron mass = 24.1913 amu

Note that the mass defect is:

Mass defect = Actual mass - Theoretical mass : 24.30506 amu- 24.1913 amu= 0.11376 amu

Calculating the binding energy per nucleon:

\frac{B.E.}{nucleon}=\frac{(0.11376amu)(931Mev/amu}{24nucleons}  = 4.41294 Mev/nucleon

So approximately 4.41294 Mev/necleon


3 0
3 years ago
Other questions:
  • What happens when you drink water that was in the car heated then you drink it. Make sure to explain your answer to make you as
    5·2 answers
  • An airplane flies at an altitude of 36,000 km and is traveling at a velocity of 300.0 km/h to the north, but the tailwind is 20.
    14·2 answers
  • what are some examples of how we interfere with ecosystems. For each example, explain how it happens, why we do it, and then men
    14·2 answers
  • Weight measures:
    6·1 answer
  • A position vector in the first quadrant has an x-component of 18 m and a magnitude of 30 m. What is the value of its y-component
    5·1 answer
  • Define force in your own words.
    12·2 answers
  • 1. Lauren’s SUV was detected exceeding the posted speed limit of 60 kilometers per hour, how many kilometers per hour would she
    14·1 answer
  • 1. Although mercury is a metal, it is a liquid at room temperature. Mercury melts at about -39°C. If
    8·1 answer
  • How many type of linear expansion physic
    15·1 answer
  • when drawing a scatter diagram, along which axis is the explanatory variable placed? along which axis is the response variable p
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!