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3 years ago

Approximately how old is the earth?

Physics

1 answer:

Wewaii [24]3 years ago

6 0

C) 4.5 billion years old

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Gas liquids will both expand to fll their containers true or false

MrMuchimi

It Is False. Liquid will not expand to fill it's container, while gas will.

6 0

3 years ago

An ideal gas is compressed isothermally to one-third of its initial volume. The resulting pressure will be

Natali5045456 [20]

Answer: a. three times as large as the initial value.

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature (isothermal).

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

We are given:

$P_1=p\\V_1=v\\P_2=?\\V_2=\frac{v}{3}$

Putting values in above equation, we get:

$p\times v=P_2\times \frac{v}{3}\\\\P_2=3p$

Thus the resulting pressure will be three times as large as the initial value.

5 0

3 years ago

For an object to appear red, what must happen?

Lapatulllka [165]

Answer:

<h2>C. It must reflect red light wavel</h2>

Explanation:

The color of the object is reflected by the object other colors are absorbed by the object.

Here object appears in red color so red color is reflected by the object and other colors are absorbed.

3 0

3 years ago

Create a list of three questions that are good science questions.

masya89 [10]

Answer:

what is speed

how to tell what speed an objeckt is moveing

vlocity

Explanation:

5 0

4 years ago

A satellite orbiting the earth is directly over a point on the equator at 12:00 midnight every four days. It is not over that po

Mrrafil [7]

Answer:

106417026.88435 m

Explanation:

T = Time period of the satellite = 4 days

m = Mass of the Earth = 5.972 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

Time period is given by

$T=2\pi\sqrt{\dfrac{r^3}{GM}}\\\Rightarrow r=\left(\dfrac{T^2GM}{4\pi ^2}\right)^{\dfrac{1}{3}}\\\Rightarrow r=\left(\dfrac{(4\times 24\times 60\times 60)^2\times 6.67\times 10^{-11}\times 5.972\times 10^{24}}{4\pi ^2}\right)^{\dfrac{1}{3}}\\\Rightarrow r=106417026.88435\ m$

The radius of the satellite's orbit is 106417026.88435 m

5 0

3 years ago