Answer:
Given that,
Mass of the Earth m
1
=6×10
24
Kg
Mass of the Moon m
2
=7.4×10
22
kg
Distance between the Earth and the Moon d=3.84×10
5
km=3.84×10
8
m
Gravitational Constant G=6.7×10
−11
Nm
2
/kg
2
Now, by using Newton’s law of gravitation
F=
r
2
Gm
1
m
2
F=
(3.84×10
8
)
2
6.7×10
−11
×6×10
24
×7.4×10
22
F=
14.8225×10
16
297.48×10
35
F=20.069×10
19
F=20.1×10
19
N
Hence, the gravitational force of attraction is 20.1×10
19
N
Answer:
maximum force (in N) can you exert horizontally on the crate without moving it = 564.075 N
Explanation:
Given data:
mass m= 115 kg
coefficient of friction μ =0.5
according to newton law of motion the net force acted on body is given by
here the body is in rest ,
N= it is the normal reaction force
N= mg = 115×9.81
therefore,
Given :
Walk in forward direction is 30 m .
Walk in backward direction is 25 m .
To Find :
The distance and displacement .
Solution :
We know , distance is total distance covered and displacement is distance between final and initial position .
So , distance travelled is :
D = 30 + 25 m = 55 m .
Now , we first move 30 m in forward direction and then 25 m in backward direction .
So , displacement is :
D = 30 - 25 m = 5 m .
Therefore , distance and displacement covered is 55 m and 5 m respectively .
Hence , this is the required solution .
Hope this shows! It has all the equations for all of the problems u asked in the comments
