A block slides forward 4.73 m while being pulled back by a 39.7 N force at 142° from the direction of motion. How much work does
1 answer:
Answer:
work done by the force, W = -147.97 J
Given:
displacement of the box, s = 4.73 m
angle between force and displacement,
Force, F = 39.7 N
Solution:
Work done by the force can be expressed as the dot product of Force, F and displacement 's' is given by:
W = Fscos
W = 39.7
W = -147.97 J
where negative sign indicates that work is done on the block
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Answer:
(a) v = 5.42m/s
(b) vo = 4.64m/s
(c) a = 2874.28m/s^2
(d) Δy = 5.11*10^-3m
Explanation:
(a) The velocity of the ball before it hits the floor is given by:
(1)
g: gravitational acceleration = 9.8m/s^2
h: height where the ball falls down = 1.50m
The speed of the ball is 5.42m/s
(b) To calculate the velocity of the ball, after it leaves the floor, you use the information of the maximum height reached by the ball after it leaves the floor.
You use the following formula:
(2)
vo: velocity of the ball where it starts its motion upward
You solve for vo and replace the values of the parameters:
The velocity of the ball is 4.64m/s
(c) The acceleration is given by:
The acceleration of the ball is 2874.28/s^2
(d) The compression of the ball is:
THe compression of the ball when it strikes the floor is 5.11*10^-3m