All categories

2 years ago

How long will it take a person walking at 3.2 m/s to travel 16 m? *

Physics

2 answers:

Alina [70]2 years ago

8 0

Approximately 6.2 seconds

Lesechka [4]2 years ago

4 0

Answer:

5.0 s

Explanation:

The equation for time is:

$t = \frac{d}{s}$

We plug in the given values into the equation

$t=\frac{16\ m}{3.2\ m/s^}$

$t=5.0 \ s$

You might be interested in

A lawyer most likely has __________. a.spatial intelligence b.practical intelligence c.analytical intelligence d.creative intell

ArbitrLikvidat [17]

The type of intelligence required by a profession depends on its job description. Lawyers most likes have analytical intelligence.

A renowned psychologist named Howard Gardner devised a theory of multiple intelligence. This means that nobody is really not intelligent because a person must posses one or more of these multiple intelligence.

A lawyer has a lot to do with analytic reasoning and comparison of evidence to determine their validity. This task requires a strong analytical mind hence a lawyer requires analytical intelligence.

Learn more: brainly.com/question/4158015

3 0

2 years ago

The part of the scientific method where we record data is the

tensa zangetsu [6.8K]

The answer is d. experiment

3 0

3 years ago

Read 2 more answers

Which instrument is used to measure the height of a 20 litre jerrican

Lynna [10]

tape measure?

Hope that helped!!! k

7 0

3 years ago

Read 2 more answers

A ball is thrown with a speed of 20 m/s at an angle of 40o above the horizontal from the top of a 22-m tall building.

MrRissso [65]

Answer:

(a). The distance is 49.79 m.

(b). The speed of the ball is 24.39 m/s.

Explanation:

Given that,

Speed = 20 m/s

Angle = 40°

Height = 22 m

Time = 3.25 sec

(a). We need to calculate the distance

Using formula of distance

$d=u\cos\theta\times t$

Put the value into the formula

$d=20\cos40\times3.25$

$d=49.79\ m$

(b). We need to calculate the horizontal velocity

Using formula of velocity

$v_{x}=u\cos\theta$

Put the value into the formula

$v_{x}=20\times\cos40$

$v_{x}=15.3\ m/s$

We need to calculate the vertical velocity

Using equation of motion

$v_{y}=u\sin\theta-gt$

Put the value into the formula

$v_{y}=20\sin40-9.8\times3.25$

$v_{y}=-19\ m/s$

Negative sign shows the opposite direction.

We need to calculate the speed of ball

Using formula of speed

$v=\sqrt{v_{x}^2+v_{y}^2}$

$v=\sqrt{(15.3)^2+(19)^2}$

$v=24.39\ m/s$

Hence, (a). The distance is 49.79 m.

(b). The speed of the ball is 24.39 m/s.

4 0

2 years ago

Most automobiles have a coolant reservoir to catch radiator fluid that may overflow when the engine is hot. A radiator is made o

Colt1911 [192]

Answer:

There is a loss of fluid in the container of 0.475L

Explanation:

To solve the problem it is necessary to take into account the concepts related to the change of voumen in a substance depending on the temperature.

The formula that describes this thermal expansion process is given by:

$\Delta V = \beta V_0 \Delta T$

Where,

$\Delta V =$ Change in volume

$V_0 =$ Initial Volume

$\Delta T =$ Change in temperature

$\beta =$ coefficient of volume expansion (Coefficient of copper and of the liquid for this case)

There are two types of materials in the container, liquid and copper, so we have to change the amount of Total Volume that would be subject to,

$\Delta V_T = \Delta V_l - \Delta V_c$

Where,

$\Delta V_l$ = Change in the volume of liquid

$\Delta V_c$ = Change in the volume of copper

Then replacing with the previous equation we have:

$\Delta V = \beta_l V_0 \Delta T- \beta_c V_0 \Delta T$

$\Delta V = (\beta_l-\beta_c)V_0\Delta T$

Our values are given as,

Thermal expansion coefficient for copper and the liquid to 20°C is

$\beta_c = 51*10^{-6}/\°C$

$\beta_l = 400*10^{-6}/\°C$

$V_0 = 16L$

$\Delta T = (95\°C-10\°C)$

Replacing we have that,

$\Delta V = (\beta_l-\beta_c)V_0\Delta T$

$\Delta V = (400*10^{-6}/\°C-51*10^{-6}/\°C)(16L)(95\°C-10\°C)$

$\Delta V = 0.475L$

Therefore there is a loss of fluid in the container of 0.475L

6 0

3 years ago