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REY [17]
2 years ago
15

During a lunar eclipse, the moon appears to be darkened because _______________ is casting a shadow on it.

Chemistry
1 answer:
stealth61 [152]2 years ago
4 0

Answer:

the earth

Explanation:

because the moon is blocking the light of the sun

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The pH of an unknown strong acid is 2. What<br> is the hydronium ion concentration?
MissTica

Answer: Finding the [H3O+] and pH of Strong and Weak Acid Solutions The larger the Ka, the stronger the acid and the higher the H+ concentration at equilibrium. hydronium ion, H3O+, 1.0, 0.00, H2O, 1.0×10−14, 14.00.

Explanation:The hydrogen ion in aqueous solution is no more than a proton, a bare ... the interaction between H+ and H2O .

8 0
3 years ago
Liquid nitrogen is cold and can be used to cool objects to -196°C. If you put the bottle of warm air in liquid nitrogen at this
vampirchik [111]

Answer:

Explanation:

It depends on how this is done. If you raise the pressure, the nitrogen will disappear (liquify) and all that will be left will be the 21 % oxygen and the 1% argon.

The process is very complicated because the boiling point of nitrogen keeps on changing. The boiling point is unstable.

6 0
2 years ago
How do solve for density?
Pachacha [2.7K]
Density(D) is defined as Mass(M) divided by Volume(V).

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D = M / V.

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I hope this helps!
7 0
2 years ago
How can you tell that a gas is a halogen? ___?
OLEGan [10]
If it is located at the second to last row of the periodic table (the halogen family), has seven electrons on it's outer shell, and has an oxidation number of -1, it is a halogen.
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8 0
3 years ago
The enthalpies of formation of the compounds in the combustion of methane, , are CH4 (g): Hf = –74.6 kJ/mol; CO2 (g): Hf = –393.
algol [13]

Answer:

The amount of energy released from the combustion of 2 moles of methae is 1,605.08 kJ/mol

Explanation:

The chemical reaction of the combustion of methane is given as follows;

CH₄ (g) + 2O₂ (g) → CO₂ (g) + 2H₂O (g)

Hence, 1 mole of methane combines with 2 moles of oxygen gas to form 1 mole of carbon dioxide and 2 moles of water vapor

Where:

CH₄ (g): Hf = -74.6 kJ/mol

CO₂ (g): Hf = -393.5 kJ/mol

H₂O (g): Hf = -241.82 kJ/mol

Therefore, the combustion of 1 mole of methane releases;

-393.5 kJ/mol × 1 + 241.82 kJ/mol × 2 + 74.6 kJ/mol = -802.54 kJ/mol

Hence the combustion of 2 moles of methae will rellease;

2 × -802.54 kJ/mol or 1,605.08 kJ/mol.

8 0
3 years ago
Read 2 more answers
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