Answer:
9.63 L.
Explanation:
Hello,
In this case, the undergoing chemical reaction is:

So the consumed amounts of hydrochloric acid and bromine are the same to the beginning based on:

In such a way, the yielded moles of hydrobromic acid and chlorine are:

Thus, the volume of the sample, after the reaction is the same as no change in the total moles is evidenced, that is 9.63L.
Best regards.
Answer:
B?
Explanation:
In the example, the amount of hydrogen is 202,650 x 0.025 / 293.15 x 8.314472 = 2.078 moles. Use the mass of the hydrogen gas to calculate the gas moles directly; divide the hydrogen weight by its molar mass of 2 g/mole. For example, 250 grams (g) of the hydrogen gas corresponds to 250 g / 2 g/mole = 125 moles.
<span>Express the answer in scientific notation and with the correct number of significant figures:
(6.32 x 10-4) ÷ 12.64
5.00 x 10^-5</span>