Which formula can be used to calculate the molar mass of ammonia
1 answer:
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Answer : The molar mass of the unknown gas will be 79.7 g/mol
Explanation : To solve this question we can use graham's law;
Now we can use nitrogen as the gas number 2, which travels faster than gas 1;
So, 167 / 99 = 1.687 So the nitrogen gas is 1.687 times faster that the unknown gas 1
We can compare the rates of both the gases;
So here, Rate of gas 2 / Rate of gas 1 =
Now, 1.687 = square root [ ]
When we square both the sides we get;
2.845 = (molar mass 1) / (28.01 g/mol N2)
On rearranging, we get,
2.845 X (28.01 g/mol N2) = Molar mass 1
So the molar mass of unknown gas will be = 79.7 g/mol
Answer :
(a) The name for is titanium(IV) oxide.
(b) The name for is barium chloride.
(c) The name for is copper(III) chloride.
(d) The name for is potassium iodide.
(e) The name for is strontium chloride.
(f) The name for is copper(II) bromide.
Explanation :
Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.
Ionic compound are usually formed when a metal reacts with a non-metal.
The nomenclature of ionic compounds is given by:
1. Positive ion is written first.
2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.
3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.
(a)
is an ionic compound because titanium element is a metal and oxygen element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on tin is (+4) and the the charge on oxygen is (-2). Thus, the name for is titanium(IV) oxide.
(b)
is an ionic compound because barium element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on barium is (+2) and the the charge on chlorine is (-1). Thus, the name for is barium chloride.
(c)
is an ionic compound because copper element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on copper is (+3) and the the charge on chlorine is (-1). Thus, the name for is copper(III) chloride.
(d)
is an ionic compound because potassium element is a metal and iodine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on potassium is (+1) and the the charge on iodine is (-1). Thus, the name for is potassium iodide.
(e)
is an ionic compound because strontium element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on strontium is (+2) and the the charge on chlorine is (-1). Thus, the name for is strontium chloride.
(f)
is an ionic compound because copper element is a metal and bromine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on copper is (+2) and the the charge on bromine is (-1). Thus, the name for is copper(II) bromide.