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Gekata [30.6K]
3 years ago
14

Which shows the weight of an atom?

Chemistry
1 answer:
sammy [17]3 years ago
3 0

Answer:

The atomic mass

Explanation:

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Flammable materials like alcohol should never be dispensed or used near True or False
galben [10]

near what like open flames? if so false unless it clarifies the solution requires alcohol then its a no go

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What effect does a quadrupling of the mass have upon the acceleration of the object
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The state in which all of the external forces acting upon an object are balanced; there is no acceleration. friction ..... quadrupling. doubling distance and quadrupling mass has the overall effect of the force
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Three factors affecting gas pressure are the amount of gas, temperature, and __________.
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It's A. volume
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What is the concentration of each ion in a solution that is prepared by dissolving 5.00 g of ammonium chloride in enough water t
const2013 [10]

Answer:

C = 0.08M

Explanation:

molar mass of AlCl3

Al =27

Cl = 35.5

27+3(35.5) =133.5g/mol

n= mass/Molar mass

n =CV

CV = mass/molar mass

C x 500 x 10^-³ = 5/133.5

C x 500 x 10^-³ = 0.04

C = 0.04/500 x 10^-³

C = 0.08M

4 0
3 years ago
The standard enthalpy change for the following reaction is 232 kJ at 298 K. 2 H2CO(g) 2 C(s,graphite) + 2 H2(g) + O2(g) ΔH° = 23
Georgia [21]

Answer:  The standard enthalpy change for this reaction is -116 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction is,

2H_2CO(g)\rightarrow 2C(s, graphite)+2H_2(g)+O_2(g)

\Delta H^0=232KJ

Now we have to determine the value of \Delta H for the following reaction i.e,

)C(s, graphite)+H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2CO(g) \Delta H^0'=?

According to the Hess’s law, if we reverse the reaction then the \Delta H will change its sign and if we half the reaction, then the

So, the value \Delta H^0' for the reaction will be:

\Delta H^0'=\frac{(-232kJ/mole)}{2}=-116kJ

Hence, the standard enthalpy change for this reaction is -116 kJ

7 0
3 years ago
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