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katrin [286]
1 year ago
8

True or false: environmental science concentrates on the study of earth's natural hazards.

Chemistry
1 answer:
algol [13]1 year ago
8 0

The correct answer for this question is 'False'

Environmental science is not the study of the earth's natural hazards

What is Environmental science?

Environmental Science is the study of physical, chemical, biological components of earth's natural environment they include air, water etc.,

The Environmental science closely studies the human impact on the earth's environment.

This field of science also helps us to know about how science effects our environment.

And the 3 main aspects of Environmental science are:

To understand the interaction between humans and environment

To understand how natural world works

To Find a way to deal with the environmental problems to live sustainably.

To know more about environmental science, click here:

brainly.com/question/13254058

#SPJ4

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The smallest unit that retains the properties of an element is a(n) _____. atom molecule proton compound neutron
Aleks [24]
The answer to your question is ATOM.
8 0
3 years ago
Given the following heats of combustion. CH3OH(l) + 3/2 O2(g) CO2(g) + 2 H2O(l) ΔH°rxn = -726.4 kJ C(graphite) + O2(g) CO2(g) ΔH
sergeinik [125]

Answer:

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

Explanation:

The formation reaction of CH_3OH will be,

C(s)+2H_2(g)+\frac{1}{2}O_2\rightarrow CH_3OH(g),\Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

C(graphite)+O_2(g)\rightarrow CO_2(g), \Delta H_1=-393.5kJ/mole..[1]

H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l), \Delta H_2=-285.8kJ/mole..[2]

CH_3OH(g)+\frac{3}{2}O_2(g)\rightarrow CO_2(g)+2H_2O(l) , \Delta H_3=-726.4kJ/mole..[3]

Now we will reverse the reaction 3, multiply reaction 2 by 2  then adding all the equations, Using Hess's law:

We get :

C(graphite)+O_2(g)\rightarrow CO_2(g) , \Delta H_1=-393.5kJ/mole..[1]

2H_2(g)+2O_2(g)\rightarrow 2H_2O(l) ,\Delta H_2=2\times (-285.8kJ/mole)=-571.6kJ/mol..[2]

CO_2(g)+2H_2O(l)\rightarrow CH_3OH(g)+\frac{3}{2}O_2(g) ,\Delta H_3=726.4kJ/mole [3]

The expression for enthalpy of formation of C_2H_4 will be,

\Delta H_{formation}=\Delta H_1+2\times \Delta H_2+\Delta H_3

\Delta H=(-393.5kJ/mole)+(-571.6kJ/mole)+(726.4kJ/mole)

\Delta H=-238.7kJ/mole

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

4 0
3 years ago
The bonds in the reactants of Figure 7-3 contained 372 kJ of chemical energy and the bonds in the products contained 350 kJ of c
satela [25.4K]

Answer: 22 kJ amount of energy is released in the following reaction.

Explanation: There are two types of reaction on the basis of amount of heat absorbed or released.

1. Endothermic reactions: These are the type of reactions in which reactants absorb heat to form the products. The energy of the reactants is less than the energy of the products.

2. Exothermic reactions: These are the type of reactions in which heat is released from the chemical reactions. The energy of the products is less than the reactants.

Sign convention for \Delta H: This value is negative for exothermic reactions and positive for endothermic reactions.

For the given chemical reaction,

Energy of the products is less than the energy of the reactants, Hence, this reaction will be a type of exothermic reaction and energy will be released during this chemical change.

Amount of energy released = (350 - 372) kJ = -22kJ

Negative sign symbolizes the energy is being released. So, 22 kJ amount of energy is released in the following reaction.

6 0
2 years ago
Explain the changes in potential energy as a chemical bond forms
weqwewe [10]
Energy is released when a chemical bond forms
7 0
3 years ago
You deposit $1000 into a savings plan at the end of each
Aloiza [94]

Answer:

FV = $3506.112

Interest = $506.112

Explanation:

We are given;

Annual deposit; A = $1000

Interest rate; i = 8% = 0.08

Number of years; n = 3

The value of the annuity after 3 years will be gotten from the formula;

FV = A[((1 + i)ⁿ - 1)/i](1 + i)

FV = 1000(((1 + 0.08)³ - 1)/0.08)(1 + 0.08)

FV = 1000(1.08⁴ - 1.08)/0.08

FV = $3506.112

Since you deposited $1000 each year, then after 3 years, total deposited = 3 × 1000 = $3000

Since FV = $3506.112, then interest = $3506.112 - $3000

Interest = $506.112

4 0
2 years ago
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