Answer:
The standard enthalpy of formation of methanol is, -238.7 kJ/mole
Explanation:
The formation reaction of CH_3OH will be,

The intermediate balanced chemical reaction will be,
..[1]
..[2]
..[3]
Now we will reverse the reaction 3, multiply reaction 2 by 2 then adding all the equations, Using Hess's law:
We get :
..[1]
..[2]
[3]
The expression for enthalpy of formation of
will be,



The standard enthalpy of formation of methanol is, -238.7 kJ/mole
Answer: 22 kJ amount of energy is released in the following reaction.
Explanation: There are two types of reaction on the basis of amount of heat absorbed or released.
1. Endothermic reactions: These are the type of reactions in which reactants absorb heat to form the products. The energy of the reactants is less than the energy of the products.
2. Exothermic reactions: These are the type of reactions in which heat is released from the chemical reactions. The energy of the products is less than the reactants.
Sign convention for
: This value is negative for exothermic reactions and positive for endothermic reactions.
For the given chemical reaction,
Energy of the products is less than the energy of the reactants, Hence, this reaction will be a type of exothermic reaction and energy will be released during this chemical change.
Amount of energy released = (350 - 372) kJ = -22kJ
Negative sign symbolizes the energy is being released. So, 22 kJ amount of energy is released in the following reaction.
Energy is released when a chemical bond forms
Answer:
FV = $3506.112
Interest = $506.112
Explanation:
We are given;
Annual deposit; A = $1000
Interest rate; i = 8% = 0.08
Number of years; n = 3
The value of the annuity after 3 years will be gotten from the formula;
FV = A[((1 + i)ⁿ - 1)/i](1 + i)
FV = 1000(((1 + 0.08)³ - 1)/0.08)(1 + 0.08)
FV = 1000(1.08⁴ - 1.08)/0.08
FV = $3506.112
Since you deposited $1000 each year, then after 3 years, total deposited = 3 × 1000 = $3000
Since FV = $3506.112, then interest = $3506.112 - $3000
Interest = $506.112