Answer: 6 triangles
Step-by-step explanation:
hope this helps :)
1)
x^2 + (3y/2z) = 7
2x^2z + 3y = 14z
3y = 14z - 2x^2z
3y = 2z(7 - x^2)
y = 2/3(z)(7 - x^2)
2)
(3zx^4) /(5+z) = 2y
3zx^4 = 2y(5+z)
3zx^4 = 10y + 2yz
34! Find the area of each of the six sides and then add them up:)
Answer:
a) y =2/3 x + 7.
b) x = -1
c) y = -4/5 x - 1/5
d) y = -3/2 x + 5/2.
Step-by-step explanation:
a) Intercept form y = mx + b where m = 2/3 and b = 7
b) y can take any value but x is always -1.
c) Slope m = (-1-3)/ (1 - -4)
= -4/5
Using point-slope form where m = -4/5 and x1 y1 = 1 , -1:
y - y1 = m(x - x1)
y - -1 = -4/5(x - 1)
y + 1 = -4/5x + 4/5
y = -4/5 x - 1/5
d) The slope m of the line perpendicular to this line is:
-1 / 2/3
m = -3/2.
When x = -1 , y = 4 so using the slope intercept form of a line
y = mx + b
4 = -3/2 * -1 + b where b = the y-intercept.
4 = 3/2 + b
b = 4 - 3/2 = 5/2.
The equation is y = -3/2 x + 5/2.
