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3 years ago

Twelve dollars times the number of hours

Mathematics

1 answer:

Veseljchak [2.6K]3 years ago

5 0

Answer:

24 times 24 which is a day is 576

Step-by-step explanation:

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‼️10 points‼️

Tamiku [17]

Answer:

<h3>The answer is option D.</h3>

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

Slope of the line using points ( 5 , - 1) and

( - 5 , 2) is

m = 2+1/ -5-5 = - 3 / 10

Equation of the line using point ( 5 , - 1) is

y + 1 = -3/10(x - 5)

y = -3/10x + 3/2 - 1

The final answer is

Hope this helps you.

4 0

3 years ago

Can someone help me ? <br> answers are written below on picture sorry for handwriting

andrew11 [14]

I think it's 60
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3 0

3 years ago

Read 2 more answers

Which point is between points C and E?<br> B.<br> R.<br> T<br> A

Fantom [35]

Sum sum sum sum sum sums calculator use google to find sum times 9$

7 0

3 years ago

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

6 0

2 years ago

The ratio of two numbers is 4:9. When 5 is subtracted from each of them the new ratio becomes 3:8. Find the numbers.

natta225 [31]

Answer:

FIRST NUMBER IS 20

AND

SECOND NUMBER IS 45

Step-by-step explanation:

LET THE RATIO BE X

FIRST NUMBER = 4X

SECOND NUMBER = 9X

A/Q,

=}4X - 5 / 9X - 5 = 3 / 8

CRISS CROSS,

=}8 ( 4X - 5 ) = 9X - 5 ( 3 )

=}32X - 40 = 27X - 15

=}32X - 27X = - 15 + 40

=}5X = 25

=}X = 25 / 5

=}X = 5

THEREFORE,

FIRST NUMBER

=} 4X

=} 5 × 4

=} 20

SECOND NUMBER

=} 9X

=} 5 × 9

=} 45

8 0

3 years ago