Answer:
125/12
Step-by-step explanation:
1st problem-no
2nd problem-yes
3rd problem-yes
4th problem-no
Answer:
( 0.6 t^2 + 3t + 11 ) cm
Step-by-step explanation:
dh/dt = 1.2t + 3
at t = 0, h = 11 cm
(a)
dh / dt = 1.2 t + 3
dh = (1.2 t + 3) dt
integrate on both sides
h = 0.6 t^2 + 3t + c .... (1)
where c is the integrating constant
put t = 0
11 = c
Put in equation (1) , we get
h = ( 0.6 t^2 + 3t + 11 ) cm
Thus, teh height of tree after t years is given by
( 0.6 t^2 + 3t + 11 ) cm.
Answer:
2x + 6
Step-by-step explanation:
= 2(x + 3)
= 2(x) + 2(3)
= 2x + 6
Answer:
970,200
Step-by-step explanation:
In a 100 man race, how many runners have the chance to finish first?
Answer 100.
Now that 1 person is first, how many runners could be second? Well, there are still 99 runners left, and any one of them could be second.
Answer 99.
How many can be third? Using the same idea as above, once one person is first and another is second, that leaves 98 people still running and trying for third. So how many can be in third?
Answer 98.
Now you need to do the math.
100 × 99 × 98 = 970,200
So there are 970,200 different ways.
Hope this helps!! Brainliest :) ?
