DIFFERENTIATION
6+f(28+b(4)=6+112f+4bf
b=6+112f/-4f
b=1*6^0+1*112f^0/1*-4f^0
b=1+1/1
b=2
Answer:
Step-by-step explanation:
I think it's 64
Answer:
y = (3/5)x+26/5 or 5y = 3x+26
Step-by-step explanation:
Applying,
The equation of a line in two point form
(y₂-y₁)/(x₂-x₁) = (y-y₁)/(x-x₁)............... Equation 1
From the question,
Given: y₂ = 7, y₁ = 4, x₂ = 3, x₁ = -2
Substitute these values into equation 1
(7-4)/[3-(-2)] = (y-4)/(x+2)
3/5 = (y-4)/(x+2)
5(y-4) = 3(x+2)
5y-20 = 3x+6
5y = 3x+6+20
5y = 3x+26
y = (3/5)x+26/5
Hence the equation of the line is y = (3/5)x+26/5 or 5y = 3x+26
Answer:
a=-4
b=2
c=7
so therefore a*b*c=-4*2*7
