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Yanka [14]
3 years ago
5

4/5 decomposed in 2 different ways

Mathematics
1 answer:
QveST [7]3 years ago
7 0
2/3. 5/6 1/2 any work I don't k ow of this is right but it's how I learned it
You might be interested in
In Argentina, a cow on a ranch is expected to need an average of 4200 m2
nika2105 [10]

The cows of Argentina needs an approximate area of 4200 m² for grazing, and there is a total of 4500 cows.

And we are asked to find the total area of their grazing but in hectares. So, we can write:

1 \: cow = 4200 \:  {m}^{2}

Then, for 4500 cows:

4500 \: cows = 4200 \:  {m}^{2}  \times 4500

4500 \: cows = 18900000 \: m {}^{2}

We know that, 1 hectares = 10000 m² = 10⁴ m²

Then let the area of the field be x in hectares:

1 \: hectare = 10000 \:  {m}^{2}

x \: hectare = 18900000 \:  {m}^{2}

Then, putting them in proportion, We will get:

x =  \dfrac{18900000}{10000} hectares

x =  \boxed{ 1890 \: hectares}

So, the total area in hectares = <u>1</u><u>8</u><u>9</u><u>0</u><u> </u><u>hectares</u><u>.</u>

And we are done !!

#CarryOnLearning

<u>━━━━━━━━━━━━━━━━━━━━</u>

6 0
3 years ago
The bar graph shows the number of school days Jalen had homework and did not have homework during the first six months of
Oksanka [162]

Given:

<u>In July:</u>

Number of days he has done the homework = 6

Number of days he has not done the homework = 4

<u>In August:</u>

Number of days he has done the homework = 16

Number of days he has not done the homework = 7

<u>In September:</u>

Number of days he has done the homework = 14

Number of days he has not done the homework = 4

<u>In October:</u>

Number of days he has done the homework = 14

Number of days he has not done the homework = 8

<u>In November:</u>

Number of days he has done the homework = 16

Number of days he has not done the homework = 4

<u>In December:</u>

Number of days he has done the homework = 5

Number of days he has not done the homework = 10

To find the months in which the difference between the number of days with homework and with no homework greater than 6.

Now,

<u>In July,</u>

The difference between the number of days with homework and with no homework = 6-4 = 2

<u>In August,</u>

The difference between the number of days with homework and with no homework = 16-7 = 9

<u>In September,</u>

The difference between the number of days with homework and with no homework = 14-4 = 10

<u>In October,</u>

The difference between the number of days with homework and with no homework = 14-8 = 6

<u>In November,</u>

The difference between the number of days with homework and with no homework = 16-4 = 12

<u>In December,</u>

The difference between the number of days with homework and with no homework = 10-5 = 5

Hence,

In 3 months the difference between the number of days with homework and with no homework greater than 6 and these are: August, September, November.

4 0
3 years ago
Craig ran 4 days last week. His distances were
elixir [45]
6.875 average.

To calculate the average you add up all of the numbers and divide it by the number of numbers there are, in this case there are 4 numbers. So you add 3.25+6.5+7.25+10.5 and divide that by 4
8 0
2 years ago
A cardboard box without a lid is to be made with a volume of 4 ft 3 . Find the dimensions of the box that requires the least amo
Blababa [14]

Answer:

<h2><em>2ft by 2ft by 1 ft</em></h2>

Step-by-step explanation:

Total surface of the cardboard box is expressed as S = 2LW + 2WH + 2LH where L is the length of the box, W is the width and H is the height of the box. Since the cardboard box is without a lid, then the total surface area will be expressed as;

S  = lw+2wh+2lh ... 1

Given the volume V = lwh = 4ft³ ... 2

From equation 2;

h = 4/lw

Substituting into r[equation 1;

S = lw + 2w(4/lw)+ 2l(4/lw)

S = lw+8/l+8/w

Differentiating the resulting equation with respect to w and l will give;

dS/dw = l + (-8w⁻²)

dS/dw = l - 8/w²

Similarly,

dS/dl = w  + (-8l⁻²)

dS/dw = w - 8/l²

At turning point, ds/dw = 0 and ds/dl = 0

l - 8/w² = 0 and w - 8/l² = 0

l = 8/w²  and w =8/l²

l = 8/(8/l² )²

l = 8/(64/I⁴)

l = 8*l⁴/64

l = l⁴/8

8l = l⁴

l³ = 8

l = ∛8

l = 2

Hence the length of the box is 2 feet

Substituting l = 2 into the function l = 8/w² to get the eidth w

2 = 8/w²

1 = 4/w²

w² = 4

w = 2 ft

width of the cardboard is 2 ft

Since Volume = lwh

4 = 2(2)h

4 = 4h

h = 1 ft

Height of the cardboard is 1 ft

<em>The dimensions of the box that requires the least amount of cardboard is 2ft by 2ft by 1 ft</em>

8 0
3 years ago
I cant do it sombody help
motikmotik

Step-by-step explanation:

hope this helps. in the first part you set the problems equal to each other. in the second, you get rid of one letter, then solve.

3 0
3 years ago
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