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3 years ago

Pls someone help me

Mathematics

1 answer:

jarptica [38.1K]3 years ago

4 0

Answer:

Upper left corner

Step-by-step explanation:

Divide the distance D over the time T. If you travel D = 325 miles for T = 5 hours, then your speed or rate R is

R = D/T = 325/5 = 65

So you're traveling at 65 miles an hour if you travel 325 miles in 5 hours, which is what the upper left corner diagram is showing.

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HELPPPPP meeeee plsss

Karo-lina-s [1.5K]

Answer:

720

Step-by-step explanation:

50/8=6.25

4,500/6.25=720

4 0

2 years ago

What is two-thirds a number plus 4 is 7

andriy [413]

2/3x + 4 = 7
   -4    -4
4 cancels out.
2/3x = 3
x 3    x3
6/3 = 2x = 9
   /2 /2
2 cancels out.
x = 9/2 = 4.5

3 0

3 years ago

Read 2 more answers

A metalworker has a metal alloy that is 15% copper and another alloy that is 75% copper. How many kilograms of each alloy shou

lisov135 [29]

48 kilograms of 15 % copper is combined with 72 kilograms of 75 % copper to create 120 kg of a 51% copper alloy

Solution:

Let "x" be the kilograms of 15 % copper

Then, (120 - x) be the kilograms of 75 % copper

Then, according to question,

"x" kilograms of 15 % copper is combined with (120 - x) kilograms of 75 % copper to create 120 kg of a 51% copper alloy

Thus we frame a equation as:

15 % of x + 75 % of (120 - x) = 51 % of 120

Solve the equation for "x"

$15 \% \times x + 75 \% \times (120-x) = 51 \% \times 120\\\\\frac{15}{100} \times x + \frac{75}{100} \times (120-x) = \frac{51}{100} \times 120\\\\0.15x + 0.75(120-x) = 0.51 \times 120\\\\0.15x + 90 - 0.75x = 61.2\\\\0.6x = 90 - 61.2\\\\0.6x = 28.8\\\\Divide\ both\ sides\ by\ 0.6\\\\x = 48$

Thus 48 kilograms of 15 % copper used

Then, (120 - x) = (120 - 48) = 72

Thus, 72 kilograms of 75 % copper is used

4 0

2 years ago

Sam puts $500 in the bank and does not put any more money in or take any out for eight years. He receives 6% interest yearly, co

drek231 [11]

Answer:

$894

Step-by-step explanation:

0.06 x 500 x 8^1.25 (-9)= 500+ 403 = $903-9= $894

1.25 = 1/8 of 1 (-9)

1=each power.

8th year = $843.75

9th year = $894

Semi annually you can do the same as 16/1 -17

5 0

3 years ago

What is the interquartile range of this data?

jok3333 [9.3K]

Hello!

To find the interquartile range you subtract the lower quartile by the higher quartile

33 - 25 = 8

The answer is C)8

Hope this helps!

6 0

3 years ago