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kotegsom [21]
3 years ago
15

3.) You are wrapping a present in shape of a tube,

Mathematics
1 answer:
Lapatulllka [165]3 years ago
5 0
No. surface area is: 2x2x2xpi (2 circle ends) + 4x12xpi (long round outside) = 175.99 ft
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A real estate agent has 14 properties that she shows. She feels that there is a 50% chance of selling any one property during a
Ratling [72]

Answer:

91.02% probability of selling more than 4 properties in one week.

Step-by-step explanation:

For each property, there are only two possible outcomes. Either it is sold, or it is not. The chance of selling any one property is independent of selling another property. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 14, p = 0.5

Compute the probability of selling more than 4 properties in one week.

Either you sell 4 or less properties in one week, or you sell more. The sum of the probabilities of these events is decimal 1. So

P(X \leq 4)  + P(X > 4) = 1

We want to find P(X > 4). So

P(X > 4) = 1 - P(X \leq 4)

In which

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{14,0}.(0.5)^{0}.(0.5)^{14} = 0.000061

P(X = 1) = C_{14,1}.(0.5)^{1}.(0.5)^{13} = 0.000854

P(X = 2) = C_{14,2}.(0.5)^{2}.(0.5)^{12} = 0.0056

P(X = 3) = C_{14,3}.(0.5)^{3}.(0.5)^{11} = 0.0222

P(X = 4) = C_{14,4}.(0.5)^{4}.(0.5)^{10} = 0.0611

So

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.000061 + 0.000854 + 0.0056 + 0.0222 + 0.0611 = 0.0898

Finally

P(X > 4) = 1 - P(X \leq 4) = 1 - 0.0898 = 0.9102

91.02% probability of selling more than 4 properties in one week.

8 0
3 years ago
Can some one Pls help!
Vesnalui [34]

First, undo the division of 6 by multiply both sides by 6.

Then undo the subtraction by adding 5 to both sides.

\frac{(f-5)}{6} = 4\\(6)\frac{(f-5)}{6} = 4(6) \\f-5 = 24\\  +5 = +5\\f = 29

3 0
3 years ago
Can any of you help me with this
RUDIKE [14]
If f(x)=2x^2+5√(x+2) then:

f(2)=2(2^2)+5√(2+2)

f(2)=2(4)+5√4

f(2)=8+5(2)

f(2)=8+10

f(2)=18

We assume the square root is positive unless otherwise indicated because this is a function and you can have only one y value for each x value to be a function.
6 0
4 years ago
The ratio of the number of boys to the number of girls in Ms. Zombo’s class is 3 to 4. The ratio of the number of boys to the nu
MAXImum [283]

Answer:

\frac{51}{46}

Step-by-step explanation:

Number of boys = B

Number of girls = G

Ratio of the number of boys to the number of girls in Ms. Zombo’s class = \frac{3}{4}

\frac{B}{G}=\frac{3}{4}\\\Rightarrow B=G\frac{3}{4}

B+G=49\\\Rightarrow G\frac{3}{4}+G=49\\\Rightarrow G\frac{7}{4}=49\\\Rightarrow G=28

B=G\frac{3}{4}\\\Rightarrow B=28\frac{3}{4}\\\Rightarrow B=21

Ratio of the number of boys to the number of girls in Mr. Stolarski’s class = \frac{5}{3}

\frac{B}{G}=\frac{5}{3}\\\Rightarrow B=G\frac{5}{3}

B+G=48\\\Rightarrow G\frac{5}{3}+G=48\\\Rightarrow G\frac{8}{3}=49\\\Rightarrow G=18

B=G\frac{8}{3}\\\Rightarrow B=18\frac{5}{3}\\\Rightarrow B=30

Total number of boys in combined class = 21+30 = 51

Total number of girls in combined class = 28+18 = 46

∴ Ratio of the number of boys to girls in the combined classes is \mathbf{\frac{51}{46}}

8 0
3 years ago
If f(1)=7 and f(n)=3f(n-1)+3 then find the value of (3)
Helen [10]

Given:

f(1)=7

f(n)=3f(n-1)+3

To find:

The value of f(3).

Solution:

We have,

f(n)=3f(n-1)+3               ...(i)

Substituting n=2 in (i), we get

f(2)=3f(2-1)+3

f(2)=3f(1)+3

Substituting f(1)=7 in the above equation, we get

f(2)=3(7)+3

f(2)=21+3

f(2)=24

Now, substituting n=3 in (i), we get

f(3)=3f(3-1)+3

f(3)=3f(2)+3

Substituting f(2)=24 in the above equation, we get

f(3)=3(24)+3

f(3)=72+3

f(3)=75

Therefore, the value of f(3) is 75.

6 0
3 years ago
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