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Anna71 [15]
3 years ago
13

How many counting numbers have three distinct nonzero digits such that the sum of the three digits is 7?​

Mathematics
1 answer:
SOVA2 [1]3 years ago
7 0

Answer:

6

Step-by-step explanation:

You have 2 conditions.

1. The digits must be different.

2. The digits must add to 7.

There aren't very many

124

142

214

241

412

421

That's it. That's your answer. There are 6 of them

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Carlos is arranging books on shelves. He has 56 novels and 16 autobiographies. Each shelf will have the
labwork [276]

Answer:

72

Step-by-step explanation:

it would be 72 because your adding 56+16 and that equals 72 numbers he will use

8 0
3 years ago
Suppose you buy a CD for $1000 that earns 2.5% APR and is compounded
labwork [276]

The early withdrawal fee on this account is $6.25

Step-by-step explanation:

Suppose you buy a CD for $1000

  • It earns 2.5% APR and is compounded  quarterly
  • The CD matures in 5 years
  • Assume that if funds are withdrawn  before the CD matures, the early withdrawal fee is 3 months' interest

We need to find the early withdrawal fee on this account

∵ The annual interest is 2.5%

- Change it to decimal

∵ 2.5% = 2.5 ÷ 100 = 0.025

∴ The annual interest rate is 0.025

∵ The interest is compounded quarterly

∴ The interest rate per quarter = 0.025 ÷ 4 = 0.00625

∵ The early withdrawal fee is 3 months' interest

∵ You buy the CD for $1000

∵ A quarter year = 3 months

∴ The early withdrawal fee = 1000 × 0.00625 = $6.25

The early withdrawal fee on this account is $6.25

Learn more:

You can learn more about the interest in brainly.com/question/11149751

#LearnwithBrainly

7 0
3 years ago
Help writing linear inequalities
pashok25 [27]

y>3x+6

y>4/3x-5 <- (The sign is greater than or equal to btw)

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In Exercises 10 and 11, points B and D are points of tangency. Find the value(s) of x.<br>​
Lemur [1.5K]

In both cases,

AB^2=AD^2

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

(4x+7)^2=(6x-3)^2

16x^2+56x+49=36x^2-36x+9

20x^2-92x-40=0

5x^2-23x-10=0

(5x+2)(x-5)=0\implies\boxed{x=5}

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

(4x^2-18x-10)^2=(x^2+x+4)^2

16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16

15x^4-146x^3+235x^2+352x+84=0

(x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}

(again, omit the solutions that would give a negative length for either AB or AD)

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3 years ago
Which equation demonstrates the additive identity property?
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Answer:

first you have to add

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