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bija089 [108]
4 years ago
15

Sort the characteristics of states of matter based on whether they change. the volume of a solid the shape of a solid the volume

of a liquid the shape of a liquid the volume of a gas the shape of a gas
Physics
1 answer:
alekssr [168]4 years ago
3 0

The volume of a solid is stable, the shape of a solid is stable.


The volume of a liquid is stable, the shape of a liquid is not stable.


The volume of a gas is not stable, the shape of a gas is not stable

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• t2<span>). Furthermore, since there is no horizontal acceleration, the horizontal distance traveled by the projectile each second is a constant value - the projectile travels a horizontal distance of </span>20 meters<span> each second. This is consistent with the initial horizontal velocity of </span>20 m<span>/s.

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bearhunter [10]

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3 years ago
For a freely falling object weighing 3 kg : A. what is the object's velocity 2 s after it's release. B. What is the kinetic ener
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A) 19.6 m/s (downward)

B) 576 J

C) 19.6 m

D) Velocity: not affected, kinetic energy: doubles, distance: not affected

Explanation:

A)

An object in free fall is acted upon one force only, which is the force of gravity.

Therefore, the motion of an object in free fall is a uniformly accelerated motion (constant acceleration). Therefore, we can find its velocity by applying the following suvat equation:

v=u+at

where:

v is the velocity at time t

u is the initial velocity

a=g=9.8 m/s^2 is the acceleration due to gravity

For the object in this problem, taking downward as positive direction, we have:

u=0 (the object starts from rest)

a=9.8 m/s^2

Therefore, the velocity after

t = 2 s

is:

v=0+(9.8)(2)=19.6 m/s (downward)

B)

The kinetic energy of an object is the energy possessed by the object due to its motion.

It can be calculated using the equation:

KE=\frac{1}{2}mv^2

where

m is the mass of the object

v is the speed of the object

For the object in the problem, at t = 2 s, we have:

m = 3 kg (mass of the object)

v = 19.6 m/s (speed of the object)

Therefore, its kinetic energy is:

KE=\frac{1}{2}(3)(19.6)^2=576 J

C)

In order to find how far the object has fallen, we can use another suvat equation for uniformly accelerated motion:

s=ut+\frac{1}{2}at^2

where

s is the distance covered

u is the initial velocity

t is the time

a is the acceleration

For the object in free fall in this problem, we have:

u = 0 (it starts from rest)

a=g=9.8 m/s^2 (acceleration of gravity)

t = 2 s (time)

Therefore, the distance covered is

s=0+\frac{1}{2}(9.8)(2)^2=19.6 m

D)

Here the mass of the object has been doubled, so now it is

M = 6 kg

For part A) (final velocity of the object), we notice that the equation that we use to find the velocity does not depend at all on the mass of the object. This means that the value of the final velocity is not affected.

For part B) (kinetic energy), we notice that the kinetic energy depends on the mass, so in this case this value has changed.

The new kinetic energy is

KE'=\frac{1}{2}Mv^2

where

M = 6 kg is the new mass

v = 19.6 m/s is the speed

Substituting,

KE'=\frac{1}{2}(6)(19.6)^2=1152 J

And we see that this value is twice the value calculated in part A: so, the kinetic energy has doubled.

Finally, for part c) (distance covered), we see that its equation does not depend on the mass, therefore this value is not affected.

5 0
3 years ago
A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 19.0 m/s when the
german

Answer: 4 s

Explanation:

Given

The ball leaves the hand of student with a speed of u=19\ m/s

When the hand is h=2.5\ m above the ground

Using the equation of motion we can write

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A student stands on the ground with an egg in his hand. He throws the
umka21 [38]

The maximal potential energy is present at the highest point, and there is no kinetic energy due to the zero ultimate velocity at the lowest point.

<h3>What is potential energy?</h3>

The potential energy is due to the virtue of the position and the height. The unit for the potential energy is the joule.

The potential energy is mainly depending upon the height of the object.

When the egg is at the highest position, the height is maximum. Therefore, the potential energy is also maximum.

When the egg lands on the ground at the striking point only the kinetic energy exists the potential energy is zero.

According to the law of conservation of energy, total energy is defined as the sum of kinetic energy and potential energy.

Total energy = kinetic energy+potential energy

Also, the energy can not be created nor destroyed and can be transferred from one form to another form.

Hence, at the highest point potential energy is the maximum and the kinetic energy is zero. because the final velocity is zero.

To learn more about the potential energy, refer to the link;

brainly.com/question/24284560

#SPJ1

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2 years ago
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