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vladimir2022 [97]
3 years ago
8

3. A Tylenol has 80 mg of acetaminophen. How many grams is that

Physics
1 answer:
denis23 [38]3 years ago
6 0

\boxed{\sf 1g=1000mg}

\\ \sf\longmapsto 80g

\\ \sf\longmapsto \dfrac{80}{1000}

\\ \sf\longmapsto 0.08g

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A ball is thrown downward with an initial speed of 7 m / s. The ball's velocity after 3 seconds is m / s. (g = -9.8m / s²)
yan [13]

Answer:

-36.4 m/s

Explanation:

final velocity= initial velocity + acceleration x time

7 + (-9.8)(3)= -36.4 m/s

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You push a bike pedal 10cm and the bike moves 100cm. Calculate the Speed ratio ( show all work ) ( use the formula and divide th
scZoUnD [109]

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Explanation:

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Which of the following is a possible use for nuclear energy?
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Read 2 more answers
The bob of a pendulum swings back and forth with a total mechanical energy of 300 J. What is the kinetic energy of the bob when
zhenek [66]

at the lowest point in the trajector, the kinetic energy of the bob is 300 J.

Explanation:

The total mechanical energy of the bob at any point of its motion is given by

E=KE+PE

Where

KE=\frac{1}{2}mv^2 is the kinetic energy, where

m is the mass of the bob

v is its speed

PE=mgh is the gravitational potential energy, where

g is the acceleration of gravity

h is the height of the bob, measured with respect to the lowest point of the trajector

In absence of friction, the total mechanical energy E remains constant. So we have:

- When the bob swings upward, the PE increases (because h increases) and the KE decreases (so the speed decreases). At the highest point in the trajector, the speed of the bob is zero (v=0), so its KE is also zero and all the mechanical energy is potential energy: U = 300 J

- When the bob swings downward, the PE decreases (because h decreases) and the KE increases (so the speed increases). At the lowest point in the trajectory, the height has become zero (h=0), so the PE is zero and all the mechanical energy is kinetic energy: KE = 300 J

Therefore, at the lowest point in the trajector, the kinetic energy of the bob is 300 J.

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

4 0
3 years ago
A simple pendulum of length of 1.37 m and mass of 6.66 kg is given an initial speed of 2.85 m/s at its equilibrium position. Det
yawa3891 [41]

Answer:

2.35 s

Explanation:

The period of a simple pendulum is expressed as;

                                T = 2π\sqrt{\frac{L}{g} }

Where

T is the period in seconds

L is the length in metres

g is acceleration due to gravity

                                 T = 2π\sqrt{\frac{1.37}{9.8}}

                                 T = 2.349 s

                                 T = 2.35 s

8 0
3 years ago
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