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Margaret [11]
2 years ago
6

A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 19.0 m/s when the

hand is 2.50 m above the ground.
Required:
How long is the ball in the air before it hits the ground?
Physics
1 answer:
german2 years ago
5 0

Answer: 4 s

Explanation:

Given

The ball leaves the hand of student with a speed of u=19\ m/s

When the hand is h=2.5\ m above the ground

Using the equation of motion we can write

h=ut+\dfrac{1}{2}at^2

Substitute the values

\Rightarrow 2.5=-19t+0.5\times 9.8t^2\\\Rightarrow 4.9t^2-19t-2.5=0\\\\\Rightarrow t=\dfrac{19\pm \sqrt{(-19)^2-4\times 4.9\times (-2.5)}}{2\times 19}\\\Rightarrow t=4.0049\quad [\text{Neglecting the negative value of }t]

Thus, the ball will take 4 s to hit the ground.

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