A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 19.0 m/s when the
1 answer:
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Answer:
3.49 seconds
3.75 seconds
-43200 ft/s²
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
Time the parachutist falls without friction is 3.19 seconds
Speed of the parachutist when he opens the parachute 31.32 m/s. Now, this will be considered as the initial velocity
So, time the parachutist stayed in the air was 3.19+0.3 = 3.49 seconds
Now the initial velocity of the last half height will be the final velocity of the first half height.
Since the height are equal
Time taken to fall the first half is 2.65 seconds
Total time taken to fall is 2.65+1.1 = 3.75 seconds.
When an object is thrown with a velocity upwards then the velocity of the object at the point to where it was thrown becomes equal to the initial velocity.
Magnitude of acceleration is -43200 ft/s²
Answer:
Yes, it's correct
Explanation:
Newton's second Law states that the acceleration of an object is proportional to the net force applied on it, according to the equation:
where
F is the net force on the object
m is the mass of the object
a is the acceleration of the object
We can re-arrange the previous equation in order to solve explicitely for a, the acceleration, and we find:
So, we see that the acceleration is proportional to the net force and inversely proportional to the mass of the object.