All categories

3 years ago

PLEASE HELP!!

Physics

2 answers:

Hunter-Best [27]3 years ago

5 0

Answer:

C || A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.

Explanation:

Stels [109]3 years ago

5 0

Answer:

A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.

Explanation:

just took test

You might be interested in

A _______ ________ is a machine that makes work easier when a single force is applied.

svlad2 [7]

the answer is A i took a test

5 0

4 years ago

Which of the following is a science ?

emmasim [6.3K]

Answer: What do you mean which of the following is science ?

Explanation:

4 0

3 years ago

You are riding a skateboard and hit a hole in the street, causing you to fly off the board and crash. Which law represents this

alexdok [17]

Answer:

It's Laws of Motion

Explanation:

6 0

3 years ago

A +8.75 μC point charge is glued down on a horizontal frictionless table. It is tied to a -6.50 μC point charge by a light, nonc

lisov135 [29]

(a) The tension on the wire when the two charges have opposite signs is 383.5 N.

(b) The tension on the wire if both charges were negative is 3.640.25 N.

The given parameters;

first charge, q₁ = 8.75 μC
second charge, q₂ = -6.5 μC
electric field, E = 1.85 x 10⁸ N/C
distance between the two charges, r = 2.5 cm

(a)

The attractive force between the charges is calculated as follows;

$F_1 = \frac{kq_1q_2}{r^2} \\\\F_1 = \frac{(9\times 10^9) \times (8.75\times 10^{-6})\times (-6.5\times 10^{-6})}{(0.025)^2} \\\\F_1 = -819 \ N$

The force on the negative charge due to the electric field is calculated as follows;

$F_2 = Eq_2\\\\F_2 = (1.85 \times 10^8) \times (6.5 \times 10^{-6})\\\\F_2 = 1202.5 \ N$

The tension on the wire is the resultant of the two forces and it is calculated as follows;

$T = F_2 + F_1\\\\T = 1202.5 - 819\\\\T = 383.5 \ N$

(b) when the two charges are negative

The repulsive force between the two charges is calculated as follows;

$F_1 = \frac{kq_1q_2}{r^2} \\\\F_1 = \frac{(9\times 10^9) \times (-8.75\times 10^{-6})\times (-6.5\times 10^{-6})}{(0.025)^2} \\\\F_1 = 819 \ N$

The force on the first negative charge due to the electric field is calculated as follows;

$F_2 = Eq_1\\\\F_2 = (1.85 \times 10^8)\times (8.75 \times 10^{-6})\\\\F_2 = 1618.75 \ N$

The force on the second negative charge due to the electric field is calculated as follows;

$F_3 = Eq_2\\\\F_3 = (1.85 \times 10^8) \times (6.5 \times 10^{-6})\\\\F_3 = 1202.5 \ N$

The tension on the wire is the resultant of the three forces and it is calculated as follows;

$T= F_1 + F_2 + F_3\\\\T= 819 + 1618.75 + 1202.5\\\\T = 3,640.25 \ N$

Learn more here:brainly.com/question/19565286

5 0

3 years ago

How thick is the Earth's surface?

marissa [1.9K]

It is typically 30 km to 50 km thick.

3 0

4 years ago

Read 2 more answers