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kow [346]
3 years ago
5

Mobile devices offer consumers an access channel of ever-increasing importance, as demonstrated consumers’ ability to find water

bottle filling stations for Hope Springs. This is an example of a trend within the ________________ environment.
Mathematics
1 answer:
rosijanka [135]3 years ago
7 0

Answer:

technological

Step-by-step explanation:

According to my research on studies conducted by various sociologists, I can say that based on the information provided within the question this is an example of a trend within the technological environment. This is because technology helps create opportunities as well as allowing new ways of doing certain things. Like in this case finding bottle filling stations.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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Elanso [62]
-400 dollars as it it the lowest amount of money
4 0
3 years ago
Lowest to biggest -26, 31, -56, 49
MrMuchimi

Answer:-56, -26, 31, 49

7 0
3 years ago
Read 2 more answers
If f(x) = 6x – 4, what is f(x) when x = 82
sleet_krkn [62]

Answer:

f(x) = 488

Step-by-step explanation:

first you plug in 82 in for x then you multiply by 6 times 82 and you get 492 then you subtract 4 and you get 488

4 0
2 years ago
Read 2 more answers
1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat
brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

x = 1 is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

x = 2 is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) f(x) = 6x + 6/x

f\prime(x) = 6 - 6/x^2 = 0 and x \neq 0

So, the roots are x = -1 and x = 1

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum.

2) f(x)=6-4/x+2/x^2

f\prime(x)=4/x^2-4/x^3=0 and x \neq 0

So the root is x = 1

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

x = 1 is absolute minimum.

3) f(x) = 8x^2/(x-4)

f\prime(x) = (8x^2-64x)/(x-4)^2=0 and x \neq 4

So the roots are x = 0 and x = 8

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum.

4) f(x)=6(x-2)^{2/3} +4=0

f\prime(x) = 4/(x-2)^{1/3} has no solution and x = 2 is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

x = 2 is absolute minimum.

5) f(x)=8\sqrt x - 6x for x>0

f\prime(x) = (4/\sqrt x)-6 = 0

So the root is x = 4/9

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum.

5 0
2 years ago
Can someone help me please
antoniya [11.8K]

Answer:

6

Step-by-step explanation:

4 0
3 years ago
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