A room in the lower level of a cruise ship has a 30 cm diameter circular window If the midpoint of the window is 4 m below the w
ater surface, determine the hydrostatic force in Newtons acting on the window. Answer 2840N.
1 answer:
Answer:
F = 2840.3 N
Explanation:
Given:
- Diameter of window D = 0.3 m
- Midpoint of window from sea level h = 4 m
- Specific gravity of sea water S.G = 1.024
- Density of water p = 1000 kg/m^3
Find:
The hydro-static force F_r acting on the mid-point of the window.
Solution:
- The average pressure P acting on the midpoint of the window:
P = S.G p*g*h
P = 1.024*1000*9.81*4
P = 40181.76
- The hydro-static force F_r acting on the mid-point of the window:
F = P*A = P*pi*D^2 / 4
F = 40181.76*pi*0.3^2 / 4
F = 2840.3 N
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