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3 years ago

15

james wants to qualify for icp are and licensure. Which degree would be required in order to qualify for a two year master of ar

chitecture degree?

1 answer:

ololo11 [35]3 years ago

4 0

Answer:

A degree in architecture with 60 credit hours.

Explanation:

The requirements need for a student to qualify for a two year master of architecture degree are;

60 credit hours in architecture
Complete 60 credit hours in related area of profession such as; planning, landscape architecture ,public health and others.
45 credit hours in architecture course at the level of 500/600

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An engine operates on gasoline (LHV=44 MJ/kg) with a brake thermal efficiency of 37.9 % What is the brake specific fuel consumpt

scZoUnD [109]

Answer:

$s =0.21\ kg/Kw.hr$

Explanation:

Given that

Calorific value (CV) = 44 MJ/Kg

CV= 44,000 KJ/kg

Brake thermal efficiency(η) = 37.9 %

We know that

$\eta =\dfrac{BP}{\dot{m_f}\times CV}$

Where BP is the brake power

$\eta =\dfrac{BP}{\dot{m_f}\times CV}$

$0.379 =\dfrac{BP}{\dot{m_f}\times 44000}$

$\dfrac{BP}{\dot{m_f}}=16676$

Brake specific fuel consumption (s)

$s =\dfrac{\dot{m_f}}{BP}$

$s =\dfrac{3600\times \dot{m_f}}{BP}$

$s =\dfrac{3600}{16,676}\ kg/Kw.hr$

$s =0.21\ kg/Kw.hr$

7 0

3 years ago

An automobile tire with a volume of 0.8 m3 is inflated to a gage pressure of 200 kPa. Calculate the mass of air in the tire if t

saveliy_v [14]

Answer:

2.83 kg

Explanation:

Given:

Volume, V = 0.8 m³

gage pressure, P = 200 kPa

Absolute pressure = gage pressure + Atmospheric pressure

= 200 + 101 = 301 kPa = 301 × 10³ N/m²

Temperature, T = 23° C = 23 + 273 = 296 K

Now,

From the ideal gas equation

PV = mRT

Where,

m is the mass

R is the ideal gas constant = 287 J/Kg K. (for air)

thus,

301 × 10³ × 0.8 = m × 287 × 296

or

m = 2.83 kg

3 0

4 years ago

A 4 cm diameter sphere of copper is initially at a temperature of 95 °C. It is placed in a very large water bath at time t- 0. T

avanturin [10]

Answer:112.376 s

Explanation:

Given

$T_i=95^{\circ}C$

$T_f=35^{\circ}C$

$T_\infty \left ( ambient\right )=25^{\circ}C$

$h=400 watts/\left ( m^{2}^{\circ}C\right )$

$c=0.385 J/\left ( m^2^{\circ}C\right )$

$\rho =9 gm/cm^{3}$

Using Newton's law of cooling

$\frac{T_i-T_{\infty}}{T-T_{\infty}}$ = $e^{\frac{ht}{\rho L_{c}c}}$

$\frac{95-25}{35-25}$ = $e^{\frac{400\times 3\times 10^{-4}\times t}{9\times 2\times 0.385}}$

7= $e^{1.7316\times 10^{-2}\times t}$

Taking log both side

t=112.376sec

4 0

3 years ago

A three-story school has interior column bays that are spaced 25 ft apart in both directions. If the loading on the flat roof is

Lady_Fox [76]

Answer:

Explanation:

Floor Load:

Lo= 50psf

At= 25x25 = 625 square feet

$L= Lo(0.25 +15/\sqrt{KuAt)}$

$L=50(0.25+15/\sqrt{(4)(625)}$ = 13.1psf

%reduction= 13.1/50 = 26%

Fr= 3[(13.1psf)(25ft)(25ft)+(20psf)(25ft)(25ft)]= 62k

7 0

3 years ago

Which of the following types of protective equipment protects workers who are passing by from stray sparks or metal while anothe

natima [27]

Answer:

Fire/Flame resistant clothing and aprons

Explanation:

Individuals working with or around welding equipment are usually required to wear Fire/Flame resistant clothing and aprons which are designed to protect the user from various types of hazards including heat, fires , burns , and sometimes radiation. In this scenario, it would protect the individual from the welding sparks that are produced when welding, which tends to fly all over the place and can catch fire in some cases. These clothes will prevent that from happening.

7 0

3 years ago