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rewona [7]
3 years ago
8

Need help plz help me out thanks!

Mathematics
2 answers:
Elden [556K]3 years ago
6 0

Answer:

I hope this helps!

Step-by-step explanation:

3y(5x+3)=15yx+9y

2y(2x+3)=4yx+6y

4y(x+2)=4yx+8y

3y(7x+2)=21yx+6y

Elina [12.6K]3 years ago
5 0

Answer:

1. 15xy + 9y

2. 4xy + 6y

3. 4xy + 8y

4. 21xy + 6y

Step-by-step explanation:

You just have to expand it:

3y(5x+3)

= 3y(5x) + 3y(3)

= 15xy + 9y

2y(2x+3)

= 2y(2x) + 2y(3)

= 4xy + 6y

4y(x+2)

= 4y(x) + 4y(2)

= 4xy + 8y

3y(7x+2)

= 3y(7x) + 3y(2)

= 21xy + 6y

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3 0
3 years ago
The sector COB is cut from the circle with center O. The ratio of the area of the sector removed from the whole circle to the ar
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Answer:

Ratio = \frac{R^2 - r^2 }{ r^2}

Step-by-step explanation:

Given

See attachment for circles

Required

Ratio of the outer sector to inner sector

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Area = \frac{\theta}{360}\pi r^2

For the inner circle

r \to radius

The sector of the inner circle has the following area

A_1 = \frac{\theta}{360}\pi r^2

For the whole circle

R \to Radius

The sector of the outer sector has the following area

A_2 = \frac{\theta}{360}\pi (R^2 - r^2)

So, the ratio of the outer sector to the inner sector is:

Ratio = A_2 : A_1

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Cancel out common factor

Ratio = R^2 - r^2 : r^2

Express as fraction

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6 0
2 years ago
Plz help with equation of the circle will award fastest CORRECT answer with brainliest
aliina [53]

Answer:

(x-1)^2+(y-2)^2=6.25

Step-by-step explanation:

The equation for a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (h,k) is the center and r is the radius.

The center is the red dot, which is (1,2). Thus, h=1 and k=2.

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d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Let (1,2) be <em>x₁ </em>and <em>y₁ </em>and let (2.5,4) be <em>x₂ </em>and <em>y₂. </em>Therefore:

d=\sqrt{(2.5-1)^2+(4-2)^2}\\d=\sqrt{(1.5)^2+2^2}\\d=\sqrt{2.25+4}\\d=\sqrt{6.25}=2.5

Thus, r is 2.5.

Plugging these numbers into the equation, we have:

(x-h)^2+(y-k)^2=r^2\\(x-1)^2+(y-2)^2=2.5^2\\(x-1)^2+(y-2)^2=6.25

3 0
3 years ago
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