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2 years ago

2. State whether the following set are finite or infinte

Mathematics

1 answer:

Elena L [17]2 years ago

5 0

Answer:

Infinite

Finite

finite

Step-by-step explanation:

There are an infinite amount of numbers that are multpiles of 5

There are only so many africans n the world

There are two answers to this one. There is an infinite amount of numbers between 1 and 30 if you include decimals, but we're not really sure if this is what they meant by the question.

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GEOMETRY! PLEASE SHOW YOUR WORK. (updated picture)

Orlov [11]

Given:

The base of the given triangle has two part:

Left( left side of the hypotenuse) = 25

Right ( right side of the hypotenuse) = x

The altitude (h) = 60

To find the value of x.

Formula:

By Altitude rule we know that, the altitude of a triangle is mean proportional between the right and left part of the hypotenuse,

$\frac{left}{altitude} =\frac{altitude}{right}$

Now,

Putting,

left = 25, altitude = 60 and right = x we get,

$\frac{25}{60} =\frac{60}{x}$

or, $(25)(x )=(60)(60)$ [ by cross multiplication]

or, $x = \frac{3600}{25}$

or, $x = 144$

Hence,

The value of x is 144.

6 0

2 years ago

Read 2 more answers

Write (8a-^3) -2/3 in simplest form

Anna71 [15]

$(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Solution:

Given that,

$(8a^{-3})^{\frac{-2}{3}$

We have to write in simplest form

Use the following law of exponent

$(a^m)^n = a^{mn}$

Using this, simplify the given expression

$(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$