Answer:
A. the specific gravity of mixture= 2.624
B. absorption of the blend is 2.7%
Explanation:
Given that Bulk specific gravity of Aggregate A= 2.491
Given that Bulk specific gravity of Aggregate B G2=2.773
Absorption percentage of Aggregate A= 0.8%
Absorption % of Aggregate B= 4.6%
Decimal fraction of weight of Aggregate A P1=50%
Decimal fraction by weight of Aggregate B P2= 50%
The aggregate given are blended in 50% weight.
A. Composite gravity = 1/(P1/G1 + P2/G2)
Which is
1/(0.5/2.491 + 0.5/2.773)
=1/0.381
=2.624
Therefore, the specific gravity of mixture= 2.624
B. Absorption of blended aggregate is the simple weighted sum of the absorption of components.
Mathematically, it is expressed a X= P1X1 + P2X2
Where,
X1= absorption of Aggregate A
X2=absorption of Aggregate B
Absorption of blended aggregate is
(0.5x0.8) + (0.5×0.46)
= 2.7%
Therefore absorption of the blend is 2.7%
