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Ksenya-84 [330]
3 years ago
7

Determine whether or not each of the following four transaction execution histories is serializable. If a history is serializabl

e, specify a serial order of transaction execution to which it is equivalent
A. r1[x] r2[y] w2[x] r1[z] r3[z] w3[z] w1[z]
B. w1[x] w1[y] r2[u] w2[x] r2[y] w2[y] w1[z]
C. w1[x] w2[y] r2[u] w1[z] w2[x] r2[y] w1[u]
D. w1[x] w2[u] w2[y] w1[y] w3[x] w3[u] w1[z]
Engineering
1 answer:
ludmilkaskok [199]3 years ago
8 0

Answer:

Option D. w1[x] w2[u] w2[y] w1[y] w3[x] w3[u] w1[z]

Explanation:

The execution in the option D is correct. This is because there is more than one reasonable criterion.

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In C++ the declaration of floating point variables starts with the type name float or double, followed by the name of the variab
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Answer:

The given grammar is :

S = T V ;

V = C X

X = , V | ε

T = float | double

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1.

Nullable variables are the variables which generate ε ( epsilon ) after one or more steps.

From the given grammar,

Nullable variable is X as it generates ε ( epsilon ) in the production rule : X -> ε.

No other variables generate variable X or ε.

So, only variable X is nullable.

2.

First of nullable variable X is First (X ) = , and ε (epsilon).

L.H.S.

The first of other varibles are :

First (S) = {float, double }

First (T) = {float, double }

First (V) = {z, w}

First (C) = {z, w}

R.H.S.

First (T V ; ) = {float, double }

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Explanation:

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