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rjkz [21]
3 years ago
12

A Wheatstone bridge initially has resistances equal to R1 = 200Ω, R2 = 400Ω, R3=500Ω and R4=600Ω. For an input voltage of 5V, de

termine the output voltage by analysing this condition.
What is the bridge output if R1 changes to 250Ω?

Engineering
1 answer:
Masja [62]3 years ago
7 0

Answer:

A. Vo = -0.606 volts

B. Vo = -0.349 volts

Explanation:

In this question, we are asked to calculate the output voltage by analyzing the conditions given and also calculate the output voltage given that one of theses conditions changed.

Please check attachment for complete solution.

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"Water is flowing in a metal pipe. The pipe OD (outside diameter) is 61 cm. The pipe length is 120 m. The pipe wall thickness is
Katarina [22]

Answer:

Total wight =640.7927 KN

Explanation:

Given that

do= 61 cm

L =120

t= 0.9 cm

That is why inner diameter of the pipe

di= 61 - 2 x 0.9 cm

di=59.2 cm

Water density ,ρ = 1 kg/L = 1000 kg/m³

Weight of the pipe ,wt = 2500 N/m

wt = 2500 x 120 N = 300,000 N

The wight of the water

wt ' = ρ V g

wt'=1000\times \dfrac{\pi}{4}\times (0.61^2-0.0592^2)\times 9.81\times 120 N

wt'=340792.47 N

That is why total wight

Total wight = wt + wt'

Total wight =300,000+ 340792.47 N

Total wight =640,792.47 N

Total wight =640.7927 KN

7 0
4 years ago
How much force is being exerted on a 4.0 inch diameter piston if it creates a pressure of 30 psi in the system
notka56 [123]
Answer:

8000 PSI

Explanation:

I think so

4 0
3 years ago
A bullet weighing 0.08 lb is fired with a horizontal velocity of 1800 ft/s into the lower end of a slender 23-lb bar of length L
Sergeeva-Olga [200]

Answer: hello attached below is the missing image the slender weight is different from what is in the question here so I worked with 23-Ib as requested in the question

answer

≈ 12.17 Rad/sec

Explanation:

weight of bullet ( Wb ) = 0.08 Ib

horizontal velocity = 1800  ft/s

Slender(Wr) = 23-Ib bar with

length ( L ) = 30

h = 12 inches

Vro = 0

<u>Calculate the angular velocity of the bar immediately after the bullet becomes embedded  </u>

attached below is a detailed solution

6.708 = ( 0.05011 + 0.5011 ) w'

w' = 6.708 / 0.55121 ≈ 12.17 Rad/sec

6 0
3 years ago
Why is it important to know the accuracy and precision of a measuring device? Do you think that the dial caliper manufacturer’s
Leto [7]

Answer:

Accuracy and precision allow us to know how much we can rely on a measuring device readings. ±.001 as a "accuracy" claim is vague because there is no unit next to the figure and the claim fits better to the definition of precision.

Explanation:

Accuracy and Precision: the golden couple.

Accuracy and precision are key elements to define if a measuring device is reliable or not for a specific task. Accuracy determines how close are the readings from the ideal/calculated values. On the other hand, precision refers to repeatability, that is to say how constant the readings of a device are when measuring the same element at different times. One of those two key concepts may not fulfill the criteria for measuring tool to be used on certain engineering projects where lack of accuracy (disntant values from real ones) or precision (not constant readings) may lead to malfunctons and severe delays on the project development.

±.001 what unit?

The manufacturer says that is an accuracy indicator, nevertheless there is now unit stated so this is not useful to see how accurate the device is. Additionally, That notation is more used to refer to device tolerances, that is to say the range of possible values the instrument may show when reading and element. It means it tells us more about the device precision during measurments than actual accuracy. I would recommend the following to the dial calipers manufacturers to better explain its measurement specifications:

  1. Use  ±.001 as  a reference for precision. It is important to add the respective unit for that figure.
  2. Condcut test to define the actual accuracy value an present it using one of the common used units for that:  Error percentage or ppm.

3 0
3 years ago
The diameter of a cylinder is called the a.) stroke b.)bore c.) principal length d.) radius
Amiraneli [1.4K]

Answer:

b

Explanation:

7 0
4 years ago
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