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3 years ago

15

A series circuit has 4 identical lamps. The potential difference of the energy source is 60V. The total resistance of the lamps

is 20 Ω. Calculate the current through each lamp.

1 answer:

Alexxx [7]3 years ago

8 0

Answer:

$I=3A$

Explanation:

From the question we are told that:

Number of lamps $N=4$

Potential difference $V=60v$

Total Resistance of the lamp is $R= 20ohms$

Generally the equation for Current I is mathematically given by

$I=\frac{V}{R}$

$I=\frac{60}{20}$

$I=3A$

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A mercury thermometer has a cylindrical capillary tube with an internal diameter of 0.2 mm. If the volume of the thermometer and

vova2212 [387]

To solve this problem we will proceed to calculate the specific volume from the area of the cylinder and the sensitivity. Later we will calculate the volumetric coefficient of thermal expansion and finally we will be able to calculate the volume through the relation of the two terms mentioned above. Our values are

$\text{Sensitivity}= 2mm/\°C$

$\text{Internal diameter } d= 0.2mm$

$\text{Differential expansion of Hg } \lambda_L = 1.82*10^{-4}/\°C$

Let's start by calculating the specific volume which is given by

$v = \pi (\frac{d}{2})^2 \gamma$

Here,

d = Diameter

$\gamma$ = Sensitivity

Replacing our values we have

$v = (\frac{\pi}{4})(0.2mm)^2(2mm/\°C)$

$v = 0.0628mm^3 /\°C$

Now we will obtain the value of the volumetric coefficient of thermal expansion of mercury through the differential expansion coefficient of Hg whic is three times, then

$\lambda_V = 3\lambda_L$

$\lambda_V = 3(1.82*10^{-4}/\°C)$

$\lambda_V = 5.46*10^{-4}/\°C$

Finally the relation to calculate the volume the bulb must is

$\text{Specific volume} = \text{Bulb Volume} \times \text{Volumetric Coefficient}$

$v = v_B \times \lambda_V$

$v_B = \frac{v}{\lambda_V}$

$v_B = \frac{0.0628mm^3/\°C}{5.46*10^{-4}/\°C}$

$v_B = 115mm^3$

Therefore the volume that the bulb must have is $115mm^3$

5 0

3 years ago

Three masses are attached to a uniform meter stick, as shown in Figure 12.9. The mass of the meter

sp2606 [1]

At equilibrium, the sum of clockwise and anticlockwise moments about a point is zero

The mass of that balances the system is $\underline {316.\overline 6}$ kg

The normal reaction force at the fulcrum is <u>5,804.25 N</u>

Rason:

The mass of the stick = 150.0 g

Mass m₁ on the left = 50.0 g, location = 30 cm to the left of m₂

Mass m₂ on the left = 75.0 g, location = 40 cm to the left of the fulcrum

Mass m₃ on the right of the fulcrum. location = 30 cm to the right of the fulcrum

Required:

To find the mass of m₃

Solution:

Taking moment about the fulcrum, we have;

50 × (30 + 40) + 75 × (40) + 150 × 20 = m₃ × 30

9,500 = m₃×30

$m_3 = \dfrac{9,500}{30} = 316. \overline 6$

The mass of that balances the system when it is attached at the right end of the stick, m₃ = $316.\overline 6$ kg

Normal reaction at the fulcrum = (50 + 75 + 150 + $316.\overline 6$ ) × 9.81 = 5804.25

The normal reaction at the fulcrum is 5,804.25 N

Learn more about the moment of a force here:

brainly.com/question/19464450

8 0

2 years ago

The linkage is made of three pin-connected A-36 steel members, each having a cross-sectional area of 0.75 in2, Determine the mag

algol13

Answer:

0.029N

Explanation:

Pressure = displacement × density of steel × acceleration due to gravity

displacement = 0.1in = 0.1×0.0254m = 0.00254m, density of steel = 7900kg/m^3, acceleration due to gravity = 9.8m/s^2

Pressure = 0.00254×7900×9.8 = 196.65N/m^2

Force(P) = pressure × area

Area of 1 pin-connected A-36 steel member = 0.75in^2 = 4.84×10^-6m^2

Area of 3 pin-connected A-36 steel member = 3×4.84×10^-6 = 1.452×10^-5m^2

Force(P) = 196.65 × 1.4652×10^-5 = 0.0029N

8 0

4 years ago

Integrate <br>∫cos²x sinx dx<br>

Marianna [84]

Answer:

-⅓ cos³ x + C

Explanation:

∫ cos² x sin x dx

If u = cos x, then du = -sin dx.

∫ -u² du

Integrate using power rule:

-⅓ u³ + C

Substitute back:

-⅓ cos³ x + C

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4 years ago

what is the temperature difference maintained between the air temperature and the wire in a hot wire sensor?

Blizzard [7]

Answer:

A temperature sensor is installed upstream of the hot wire. The hot wire is then heated to a temperature higher than the air temperature determined by the temperature sensor. As the hot wire is cooled by the incoming air, the heating current must be increased to maintain a constant wire temperature.

Explanation:

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3 years ago