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Lerok [7]
3 years ago
15

A series circuit has 4 identical lamps. The potential difference of the energy source is 60V. The total resistance of the lamps

is 20 Ω. Calculate the current through each lamp.
Engineering
1 answer:
Alexxx [7]3 years ago
8 0

Answer:

I=3A

Explanation:

From the question we are told that:

Number of lamps N=4

Potential difference V=60v

Total Resistance of the lamp is R= 20ohms

Generally the equation for Current I is mathematically given by

 I=\frac{V}{R}

 I=\frac{60}{20}

 I=3A

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Answer:

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Provavelmente, algumas pessoas viajam na maionese quando toca-se nesse assunto. Vem em suas mentes universos paralelos e até mesmo realidades alternativas. Mas também não se trata disso.

Explanation:

Basicamente as dimensões são as facetas do que nós percebemos a ser realidade. Existem muitos debates sobre dimensões na física. Um dos que mais chamam a atenção se chama Teoria das Cordas.

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5 0
3 years ago
Why do we study National studies
Gre4nikov [31]

Answer:

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Explanation:

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3 0
2 years ago
Pls list up to five key lessons and knowledge areas that you have acquired in this course about operations management. How do yo
Aneli [31]

Explanation:

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3 0
3 years ago
After a car is jump started, you must unclip the jumper cable clips______.
drek231 [11]

Answer:

The correct answer is;

In the reverse order you connected them

Explanation:

The process of jump starting a car is as follows;

1) Connect the positive or red clip to the dead battery

2) Connect the other end of the positive or red clip to the other end of the live battery in the donor car

3) Connect the negative or black clip to the negative terminal on the live battery

4) Connect the other end of the negative or black clip to the bare metal (without paint coating) on the donor car

5) Start and idle the donor car

6) Test to see if there is electric power in the dead car. If yes, then start the dead car

By disconnecting in the reverse other, that is by first removing the black or negative terminal from the dead vehicle chassis, prevents short circuiting the system with the rest of the metals parts in vehicle body when a metal makes contact while the positive terminal is removed and the negative terminal is still on the chassis.

8 0
3 years ago
Air fl ows isentropically through a duct. At section 1, the pressure and temperature are 250 kPa and 1258C, and the velocity is
abruzzese [7]

The correct temperature is 125°C

Answer:

A) M_a1 = 0.5

B) T2 = 232.17 K

C) V2 = 611 m/s

D) m' = 187 kg/s

Explanation:

We are given;

Pressure; P1 = 250 kPa

Temperature; T1 = 125°C = 398 K

Speed; v1 = 200 m/s

Area; A2 = 0.25 m²

M_a2 = 2

A) Formula for M_a1 is given by;

M_a1 = v/a1

Where;

v is speed

a1 = √kRT

k is specific heat capacity ratio of air = 1.4

R is a gas constant with a value of R = 287 J/kg·K

T is temperature

Thus;

M_a1 = 200/√(1.4 × 287 × 398)

M_a1 = 200/399.895

M_a1 = 0.5

B) To find T2, let's first find the Stagnation pressure T0

Thus;

T0/T1 = 1 + ((k - 1)/2) × (M_a1)²

T0 = T1(1 + ((k - 1)/2) × (M_a1)²)

T0 = 398(1 + ((1.4 - 1)/2) × (0.5)²)

T0 = 398(1 + (0.2 × 0.5²))

T0 = 398 × 1.05

T0 = 417.9 K

Now,similarly;

T0/T2 = 1 + ((k - 1)/2) × (M_a2)²

T2 = T0/[(1 + ((k - 1)/2) × (M_a2)²)]

T2 = 417.9/(1 + (0.2 × 2²))

T2 = 417.9/1.8

T2 = 232.17 K

C) V2 is gotten from the formula;

T0 = T2 + (V2)²/(2C_p)

Cp of air = 1005 J/Kg.K

Thus;

V2 = √(2C_p)[T0 - T2]

V2 = √((2 × 1005) × (417.9 - 232.17))

V2 =√373317.3

V2 = 611 m/s

D) mass flow is given by the formula;

m' = ρA2•V2

Where;

ρ is Density of air with an average value of 1.225 kg/m³

m' = 1.225 × 0.25 × 611

m' = 187 kg/s

6 0
3 years ago
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