Which of the following are chemical changes? Select all correct

Biology

1 answer:

yan [13]3 years ago

5 0

Answer:

D and E

Explanation:

The others are physical methods and can be separated again.

Hope this helps :)

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You are working in an outpatient clinic when a mother brings in her 20-year-old daughter, C.J., who has type 1 diabetes mellitus

lbvjy [14]

Answer:

The additional questions are listed in the explanation

Explanation:

1. For how long has C.J. been drowsy

2. What have C.J.'s blood glucose levels been running?

3. How much fluid has C.J. been able to keep down over the past 3 days?

4. How often has C.J. been vomiting over the past 3 days?

4 0

3 years ago

Toemas’s syndrome is a autosomal dominant disease, homozygous lethal, seen at a frequency of 1 in 10,000 cats. Felines with this

Anastaziya [24]

Answer: 50% or 25% according to the genotype of the male cat.

Explanation:

The female cat is unaffected, and since this is an autosomal dominant diease, it means this cat does not have any affected alleles. Thereby, its genotype is aa. This is because dominant alleles show their effect even if the organisms only has one copy of the allele. The male cat is affected with this syndrome so its genotype is either AA or Aa. For this disease to manifest itself, only one affected allele is needed. Although both alleles can be affected so the individual can be homozygous dominant or heterozygous.

To find this we have to do a punnett square. Here, we use the gametes produced by each individual. Gametes are sex cells, egg or sperm, which only have one allele of each gene.

Assuming that the cross is between aa and AA, the gametes produced by "aa" are "a", and the gametes produced by "AA" are "A" So we are having a cross between an "a" gamete and a "A" gamete. 100% of the offspring will be Aa so it is a heterozygous, which will develope this syndrome. And, males have one Y chromosome and one X chromosomes, thereby the chances of having a male kitten is 50%. Then, to conclude, there is a 50% chances of having a male kitten with this syndrome.

And, assuming that the cross is between aa and Aa, the gametes produced by "Aa" are "A" but also "a" So we are habing a cross between an "a" gamete and "A" or "a" gamete (See picture) In this example, there is a 50% chances of having a kitten with the syndrome, because only one genotype produced (Aa) has the affected allele. And, as we said before, since there is a 50% chances of having a male kitten, we can said that there is a 25% chances of having an affected male. Because to calculate both probabilities so that they occur simultaneously, it is necessary to multiply them. That is, 0.5 x 0.5 = 0.25 x 100 = 25%.