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Kay [80]
3 years ago
8

If Magnesium Sulfide reacts with oxygen in the air, what will be produced?

Chemistry
1 answer:
sweet [91]3 years ago
6 0

IF  magnesium sulfide reacts  with  oxygen in the air  it will  produce

 magnesium oxide  +  sulfur (IV) oxide

<u><em>explanation</em></u>

magnesium  sulfide burn in  oxygen  to produce magnesium  oxide  and sulfur (iv) oxide  according to the equation below

2MgS +3O2 →2MgO +2SO2

that is  2 moles of MgS  react with  3 moles of O2  to produce 2 moles of MgO   and  2 moles of SO2

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How many atoms are in 3Mg(OH)2
Neko [114]

Answer:3 atoms of Mg 6 atoms of O and 6 atoms of H

Explanation:

7 0
3 years ago
How many moles of C2H2 are needed to react completely with 84 mol O2
Butoxors [25]

Balanced chemical equation:

2 C2H2 + 5 O2 = 4 CO2 + 2 H2O

2 moles C2H2 ---------------- 5 moles O2
moles C2H2 ------------------ 84 moles O2

moles C2H2 = 84 * 2 / 5

molesC2H2 = 168 / 5 => 33.6 moles of C2H2
4 0
3 years ago
An insulated container contains 0.3 kg of water at 20 degrees C. An alloy with a mass of 0.090 kg and an initial temperature of
Lorico [155]

Answer:

The specific heat of the alloy is 2.324 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of water = 0.3 kg = 300 grams

Temperature of water = 20°C

Mass of alloy = 0.090 kg

Initial temperature of alloy = 55 °C

The final temperature = 25°C

The specific heat of water = 4.184 J/g°C

<u>Step 2:</u> Calculate the specific heat of alloy

Qlost = -Qwater

Qmetal = -Qwater

Q = m*c*ΔT

m(alloy) * c(alloy) * ΔT(alloy) = -m(water)*c(water)*ΔT(water)

⇒ mass of alloy = 90 grams

⇒ c(alloy) = the specific heat of alloy = TO BE DETERMINED

⇒ ΔT(alloy) = The change of temperature = T2 - T1 = 25-55 = -30°C

⇒ mass of water = 300 grams

⇒ c(water) = the specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature = T2 - T1 = 25 - 20 = 5 °C

90 * c(alloy) * -30°C = -300 * 4.184 J/g°C * 5°C

c(alloy) = 2.324 J/g°C

The specific heat of the  alloy is 2.324 J/g°C

3 0
3 years ago
Formation of water: 2H2 + 1 O2 --&gt; 2H20
VLD [36.1K]

Answer:

n=15 moles H2O

1:2

x:15

x=7.5 moles of O2

3 0
2 years ago
What is the [OH-] if the [H3O+] is 1 x 10 -6?
Mariulka [41]

The answer is [OH⁻] = 1 x 10⁻⁸.

To find OH⁻, divide the ionic product of water by [H₃O⁺] as :

<u>OH⁻ + H₃O⁺ = H₂O</u>

<u />

  • [OH⁻] = 1 x 10⁻¹⁴ / 1 x 10⁻⁶
  • [OH⁻] = 1 x 10⁻⁸
5 0
2 years ago
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