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GarryVolchara [31]
2 years ago
7

Can hydrobromic acid be a valid chemical formula?

Chemistry
1 answer:
EastWind [94]2 years ago
7 0
Yes, it can - HBr is its chemical formula.
If you had other options though, then the one which wouldn't be a valid chemical formula is aluminum (III) chloride, because, since it only has one charge (+3), it is unnecessary to state it as III.
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In a coffee-cup calorimeter, 1.55 g KOH is added to 125 ml of 0.80 M HCl. The following reaction occurs. KOH(s) + HCl(aq) → H2O(
DENIUS [597]

Answe1.55 gr:

Explanation:

yes

4 0
3 years ago
How many moles make up 5.7491x1025 molecules of Dinitrogen pentoxide (N2O5)?
pav-90 [236]

Answer:

<h2>95.5 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{5.7491 \times  {10}^{25} }{6.02 \times  {10}^{23} }  \\

We have the final answer as

<h3>95.5 moles to 3 sig. figures</h3>

Hope this helps you

6 0
3 years ago
Nombor proton bagi atom K,L,M dan N adalah 8,10,5 dan 17 masing-masing. Susunan elektron bagi atom Z ialah 2.8.3. Antara unsur b
Crazy boy [7]

Answer:

I don't understand your language please

8 0
3 years ago
Read 2 more answers
A tetrahedral field presents four sets of ligand electrons, whereas an octahedral field presents six sets of ligand electrons. I
sertanlavr [38]

Answer:

For the tetrahedral case the repulsion is smaller.

Explanation:

It is smaller for the tetrahedral case because he angles for tetrahedral molecules are greater (109.5) then for octahedral molecules (90). The greater the distance between the atoms the smaller the repulsion, and so the bigger are angles the bigger is distance.

7 0
3 years ago
In the following reaction, how many liters of carbon dioxide will be produced if 250 liters of oxygen is used in the combustion
love history [14]
The balanced reaction would be:<span>

C12H22O11 + 12O2 = 12CO2 + 11H2O

We are given the amount of oxygen used in the combustion. This will be the starting point of our calculation. We use the ideal gas equation to find for the number of moles.

n = PV / RT = 1.00(250 L) / (0.08206 atm L/mol K ) 273 K
n= 11.16 mol O2

</span>11.16 mol O2<span> (12 mol CO2 / 12 mol O2) = 11.16 mol CO2

V = nRT/P =</span>11.16 mol CO2<span> x 273 K x 0.08206 atm L/mol K / 1 atm
V=250 L</span>
7 0
3 years ago
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