Answer:
The answer is (e) : phosphoglucomutase, UDP-glucose pyrophosphorylase, glycogen synthase then amylo-(1,4-1,6)-transglycosylase.
Explanation:
Phosphoglucomutase: Convert glucose-6-phosphate to glucose-1-phosphate.
UDP-glucose pyrophosphorylase: Form UDP-glucose from glucose-1-phosphate.
Glycogen synthase: Add the new glucose from UDP-glucose to the growing glycogen chain.
Amylo-(1,4-1,6)-transglycosylase: This is a branching enzyme, it initiates formation of branches evolving from the main chain.
Answer:
a.
Explanation:
Assuming that Liquid X is considered to possess a greater viscosity as well as higher surface tension than liquid Y. Then, liquid X will tend to harbour more pressure inside the liquid.
In addition to that, the greater the surface tension, the greater the force required to expand the liquid's surface area.
This in turn makes the force required to make the loop 5% wider to be greater in FX rather than FY.
Thus, option a is the correct answer.
The answer is A
According to research I have done, pure solids and liquids are not included in the equilibrium constant expression. If the concentration of a reactant in aqueous solution is increased, the position of equilibrium will move in the direction which minimises the effect of this increase in concentration, by using the added component up, to decrese it's concentration again.
