I got this. I hope this helps. :/
Answer:
1 . 
2. 
Explanation:
The more stable the ionic compound, the more is it lattice energy.
- The more the charge on the cation and the anion, the greater is the lattice energy.
- The less the size of the cation and the anion, the greater is the lattice energy.
Scandium oxide (
) is an oxide in which 
behaves as cation and 
behaves as anion.
The compounds which has higher lattice energy than scandium oxide are:
1 .
This is because the charge are same on the cation and the anion as in the case of the Scandium oxide but the size of the cation 
is smaller than . Thus, this corresponds to higher lattice energy.
2.
This is because the charge on the cation 
is greater than that of and also the size of the cation is smaller than . Thus, this corresponds to higher lattice energy.
Answer:
E. Cl2 + 2NaBr ----> Br2 + 2NaCl
Explanation:
Number of Cl molecules is 2 on the reactant and product side of the equation.
Number of Na molecules is 2 on the reactant and product side of the equation.
Number of Br molecules is 2 on the reactant and the product side of the equation.
As the reactant side is equal to the product side, the equation is balanced.
A)
1 g/cm³ --------------- 0.001 kg/cm³
5.52 g/cm³------------ ?
5.52 x 0.001 / 1
= 0.00552 kg/cm³
b) 1 g/cm³ ----------- 62.428 lb/ft³
5.52 g/cm³ ------- ?
5.52 x 62.428 / 1
= 344.60 lb/ft³
hope this helps!
