Answer:
im not sure
Explanation:
i went on here looking nobody answered yet
I guess its D.hope this helps....sorry if i'm wrong.
Answer:inform the lab instructor and get instructions
Explanation:
If you come across a chemical in the laboratory which has been wrongly labelled, do not be quick to dilute it or take any further action. The laboratory instructor who may have prepared the reagent himself or has better knowledge about the reagent should be contacted immediately so that he/she can give you instructions about what to do with the wrongly labelled reagent.
To solve this problem, let us all convert the mass of
each element into number of moles using the formula:
moles = mass / molar mass
Where,
molar mass K = 39.10 g / mol
<span>molar mass Cl = 35.45 g / mol</span>
molar mass O = 16 g / mol
<span>and mass O = 13 g – 4.15 g
– 3.76 g = 5.09 g</span>
moles K = 4.15
g / (39.10 g / mol) = 0.106 mol
<span>moles Cl = 3.76 g / (35.45 g / mol) = 0.106 mol</span>
moles O = 5.09 g / (16 g /
mol) = 0.318 mol
The ratio becomes:
0.106 K: 0.106 Cl: 0.318 O
We divide all numbers with
the smallest number, in this case 0.106. This becomes:
K: Cl: 3O
Therefore the empirical formula
is:
